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Sorular sayı doğrusu, negatif sayılar, çarpım tablosu, cebirsel ifadeler, fonksiyonlar, küpler ve çarpma işlemleri gibi konuları içermektedir. Eğitmen her soruyu detaylı olarak açıklamakta, çözüm yöntemlerini göstermekte ve zaman kazanmak için pratik taktikler sunmaktadır. 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İlk bölümde tek ve çift sayılar konusundaki ikinci testin sekiz sorusu, ikinci bölümde ise sarı ve kırmızı güllerin sayılarını bulma, a, b ve c tam sayılarının tek veya çift olma durumlarını inceleme ve f(x) fonksiyonunun değerlerini kullanarak toplam bulma gibi üç farklı problem ele alınmaktadır.","Sorular şifre oluşturma, balık sürüleri, tam sayılar, sayı doğrusu, dik üçgenler, dikdörtgenler ve fonksiyonlar gibi farklı konuları içermektedir. Her soru için eğitmen, çözüm yöntemini detaylı olarak açıklamakta ve doğru cevabı belirtmektedir. Video, tek ve çift sayıların toplama, çıkarma, çarpma ve bölme işlemlerinde nasıl davranacağı konusunda pratik bilgiler sunmaktadır."]},"endTime":730,"title":"Tek ve Çift Sayılar Matematik Test Çözüm Videosu","beginTime":0}],"fullResult":[{"index":0,"title":"Tek ve Çift Sayılar Testi Çözümü","list":{"type":"unordered","items":["İlk soruda Emre'nin oluşturduğu şifrede tekrar eden rakam yok, rakamlar çarpımı çift sayı ve rakamları toplamı tek sayıdır.","İkinci soruda balık sürülerinde en soldaki ve ortadaki balık sürülerinde bulunan toplam balık sayısı çift sayıya, en sağdaki ve ortadaki balık sürülerinde bulunan toplam balık sayısı tek sayıya eşittir.","Üçüncü soruda a ve b birer tam sayı olmak üzere (a+1)×b çarpımının sonucu çift sayıdır ve (a×b)+(b+1) çarpımının sonucu da çift 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Eğitmen, özellikle gençlere yönelik hazırlanmış bir ders formatında kare konusu ve çeşitli geometri problemlerini adım adım çözmektedir.","Video, karenin tanımı ve özellikleri ile başlayıp, ardından 19 farklı geometri problemi çözümüne geçmektedir. Problemler genellikle kareler, üçgenler, dik yamuklar ve Tangram parçaları gibi geometrik şekillerle ilgilidir. Her problem için eğitmen, çizimler yaparak Pisagor bağıntısı, kosinüs teoremi, benzer üçgenler ve eş üçgenler gibi matematiksel kavramları kullanarak detaylı çözüm adımlarını açıklamaktadır.","Videoda ayrıca hız-zaman ilişkisi, ağırlık merkezleri, döndürme hareketleri ve katlama hareketleri gibi konular da ele alınmaktadır. Öğrenciler, karelerin alan ve çevre hesaplamaları, köşegen özellikleri ve üçgenlerin özellikleri konusunda pekişme için bu videoyu kullanabilirler."]},"endTime":2586,"title":"Kare ve Geometri Problemleri Çözüm Dersi","beginTime":0}],"fullResult":[{"index":0,"title":"Kare Tanımı ve Özellikleri","list":{"type":"unordered","items":["Dört kenar uzunluğu eşit olan dikdörtgene kare denir.","Karede her köşe açısı 90 derecedir.","Karede kenar uzunlukları birbirine eşittir."]},"beginTime":10,"endTime":35,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=10&ask_summarization=1"},{"index":1,"title":"Köşegen Özellikleri","list":{"type":"unordered","items":["Karede köşegenler birbirine dik olur.","Köşegen uzunlukları birbirine eşittir.","Köşegenler bulundukları köşelerin açıortay olup, 45'er derecelik açılar 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karesinin alanı 25, ECF karesinin alanı 4 olduğundan, DF uzunluğu √13 birim olarak hesaplanır."]},"beginTime":224,"endTime":419,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=224&ask_summarization=1"},{"index":6,"title":"Kare Problemleri","list":{"type":"unordered","items":["Dördüncü örnekte, karenin bir kenarı 16 birim, EC uzunluğu 4√2 olduğundan, x değeri 12 birim olarak bulunur.","Beşinci örnekte, EAD açısının 15 derece, AB kenarının 6√2 olduğundan, x değeri 6 birim olarak hesaplanır.","Altıncı örnekte, CA açısının 15 derece, AE uzunluğunun 4√3 olduğundan, karenin alanı 36 birim kare olarak bulunur."]},"beginTime":419,"endTime":620,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=419&ask_summarization=1"},{"index":7,"title":"Kare Problemleri","list":{"type":"unordered","items":["Yedinci örnekte, DEC üçgeni EC boyunca katlandığında oluşan açılar incelenerek alfa açısının 20 derece olduğu bulunur.","Sekizinci örnekte, AEFB karesinde köşegenler dört eş üçgene böldüğünden, sarı renkli bölgenin mavi renkli bölgenin alanının 4 katı olduğu belirtilir."]},"beginTime":620,"endTime":799,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=620&ask_summarization=1"},{"index":8,"title":"Kare Problemleri","list":{"type":"unordered","items":["Kare köşegeni, kareyi iki eşit üçgene böler ve bu üçgenlerin alanları birbirine eşittir.","Sarı renkli bölgenin alanı mavi renkli bölgenin alanının üç katıdır.","Karede, kenar uzunluğu 6 cm olan bir karenin alanı 36 cm²'dir ve DEC üçgeninin alanı 12 cm² olduğuna göre DE uzunluğu 4 cm, x değeri ise 2 cm'dir."]},"beginTime":802,"endTime":875,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=802&ask_summarization=1"},{"index":9,"title":"İkizkenar Dik Üçgen Problemi","list":{"type":"unordered","items":["Karede B açıortay ve EC=6 olduğunda, ikizkenar dik üçgen özellikleri kullanılarak EBC üçgeninde EB=6 cm bulunur.","BC dik üçgeninde hipotenüs, bir kenarının kök 2 katıdır, bu nedenle BC=6 kök 2 cm, ET=3 kök 2 cm olarak hesaplanır."]},"beginTime":875,"endTime":984,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=875&ask_summarization=1"},{"index":10,"title":"Eş Karelerden Oluşan Şekil","list":{"type":"unordered","items":["Üç tane eş kareden oluşan bir şeklin çevresi 48 cm olduğunda, karenin bir kenar uzunluğu 6 cm olarak hesaplanır.","Tüm şeklin alanı, üç karenin alanlarının toplamı olan 3×36=108 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ve v/2 değerleri bulunur.","DE'nin A'ya oranı 4 olarak hesaplanır."]},"beginTime":1106,"endTime":1236,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=1106&ask_summarization=1"},{"index":13,"title":"Kare ve Üçgen Benzerliği Problemi","list":{"type":"unordered","items":["Kare ve üçgenler arasındaki benzerlik ilişkisi kullanılarak, kenar uzunlukları arasındaki oranlar bulunur.","CFD üçgeni ile FA üçgeni benzerlik açı-açı benzerliği ile eşitlik kurulur ve kenar uzunlukları hesaplanır.","Karenin bir kenar uzunluğu 9 birim olarak bulunur ve alanı 81 birim kare olarak hesaplanır."]},"beginTime":1236,"endTime":1356,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=1236&ask_summarization=1"},{"index":14,"title":"Eş Üçgenler Problemi","list":{"type":"unordered","items":["Dik kesişen üçgenlerde açı-açı eşitliği kullanılarak, kenar uzunlukları eşitlik kurulur.","AFB üçgeni ile BEC üçgeni eşitlik kurularak kenar uzunlukları bulunur.","Karenin bir kenar uzunluğu x = √52 olarak hesaplanır ve alanı 52 birim kare olarak bulunur."]},"beginTime":1356,"endTime":1486,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=1356&ask_summarization=1"},{"index":15,"title":"Pisagor Bağıntısı Problemi","list":{"type":"unordered","items":["Kare ve üçgenler arasındaki açı ilişkileri kullanılarak, kenar uzunlukları hesaplanır.","AEB üçgeni ile BCT üçgeni eşitlik kurularak kenar uzunlukları bulunur.","CTE dik üçgeninde Pisagor bağıntısı kullanılarak x = 10 birim olarak hesaplanır."]},"beginTime":1486,"endTime":1580,"href":"/video/preview/2994001868499530011?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=1486&ask_summarization=1"},{"index":16,"title":"Hareket 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Eğitmen, Acil Matematik TYT soru bankasındaki bölme konusuyla ilgili test sorularını adım adım çözmektedir.","Videoda toplam 17 soru çözülmektedir. Sorular, beş basamaklı ve iki basamaklı doğal sayıların bölünmesi, bölüm ve kalanın toplamı, kalan değerleri, bölen ve bölüm arasındaki ilişkiler gibi konuları içermektedir. Her soru için eğitmen, çözüm yöntemini detaylı olarak anlatmakta ve gerekli hesaplamaları göstermektedir.","Video, birinci testin tamamlanmasıyla sona ermektedir. Özellikle bölme işlemlerinde kalanların nasıl kullanılacağı ve bilinmeyenlerin nasıl tek bilinmeyene çevrileceği konularında örnekler verilmektedir. TYT sınavına hazırlanan öğrenciler için bölme konusundaki pratik soru çözümlerini içermektedir."]},"endTime":1209,"title":"Acil Matematik TYT Soru Bankası: Bölme Konusu Çözümleri","beginTime":0}],"fullResult":[{"index":0,"title":"Bölme Konusuna Giriş","list":{"type":"unordered","items":["Acil Matematik TYT soru bankasının bölme konusuyla ilgili ilk testi çözülecek.","İlk soruda beş basamaklı iki basamaklı doğal sayılar verilmiş ve bölme işlemindeki bölümle kalanın toplamı 1013 olarak bulunmuş."]},"beginTime":5,"endTime":53,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=5&ask_summarization=1"},{"index":1,"title":"Bölme İşleminde Kalan Problemleri","list":{"type":"unordered","items":["İkinci soruda a ve x doğal sayıları için bölme işlemine göre a'nın en büyük değeri 133 olarak hesaplanmış.","Üçüncü soruda 27 sayısının n ile bölümünden kalan 3 olduğuna göre n'nin alabileceği değerler toplamı 54 olarak bulunmuş.","Dördüncü soruda a, b, c, 2, 4 ve mn iki basamaklı doğal sayılar için bölme işlemine göre mn sayısının alacağı değerler toplamı 52 olarak hesaplanmış."]},"beginTime":53,"endTime":227,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=53&ask_summarization=1"},{"index":2,"title":"Bölme İşleminde Değişken Değerler","list":{"type":"unordered","items":["Beşinci soruda p, q ve r üç doğal sayı için bölme işleminde bölüm ile bölen yer değiştirdiğinde kalan değişmediğine göre p'nin alacağı en küçük değer 71 olarak bulunmuş.","Altıncı soruda a pozitif doğal sayı olmak üzere verilen bölme işlemine göre a'nın en büyük değeri 8 olarak hesaplanmış."]},"beginTime":227,"endTime":325,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=227&ask_summarization=1"},{"index":3,"title":"Bölme İşlemleri ve Bilinmeyenlerin Çevrilmesi","list":{"type":"unordered","items":["Bölme işlemi için bölünen = bölen × bölüm formülü kullanılır.","Üç bilinmeyenli ifadeleri tek bilinmeyene çevirmek için, bir bilinmeyeni diğer bilinmeyenler cinsinden yazabiliriz.","Verilen bölme işlemi sonucunda a = 16c + 11 ve b = 3c + 2 olarak bulunur, c = 16 olarak hesaplanır."]},"beginTime":330,"endTime":396,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=330&ask_summarization=1"},{"index":4,"title":"Doğal Sayılarla Bölme Problemi","list":{"type":"unordered","items":["a, b ve c üç doğal sayı olmak üzere, a = 4b + 8 ve b = 3c + 1 ilişkileri verilmiştir.","a'nın en az değeri için c'nin en küçük değeri olan 2 alınır.","c = 2, b = 10 ve a = 48 olarak hesaplanır."]},"beginTime":396,"endTime":440,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=396&ask_summarization=1"},{"index":5,"title":"Bölme ve Kalan Problemi","list":{"type":"unordered","items":["Bir sayının 2079 ile bölümünden kalan 46 olduğuna göre, aynı sayının 9 ile bölümünden kalan kaçtır?","2079'un 9 ile bölümünden kalan 1 olarak bulunur.","İlk sayının 9 ile bölümünden kalan 1'e eşittir."]},"beginTime":440,"endTime":502,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=440&ask_summarization=1"},{"index":6,"title":"Çarpım ve Bölme Problemi","list":{"type":"unordered","items":["a ve b iki doğal sayı olmak üzere, a = 60k + 18 ve b = 84n + 22 ilişkileri verilmiştir.","a ile b'nin çarpımı 12 ile bölümünden kalan kaçtır?","Çarpımın 12 ile bölümünden kalan 0'a eşittir."]},"beginTime":502,"endTime":575,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=502&ask_summarization=1"},{"index":7,"title":"İki Basamaklı Sayılarla Bölme Problemi","list":{"type":"unordered","items":["x, y ve yx iki basamaklı doğal sayılar olmak üzere, bölme işlemi verilmiştir.","x ile y'nin toplamı kaçtır?","x = 4 ve y = 1 değerleri için işlem sağlanır, toplamları 5'tir."]},"beginTime":575,"endTime":641,"href":"/video/preview/16725931364221753261?parent-reqid=1769560907189493-2287723628922945850-balancer-l7leveler-kubr-yp-sas-196-BAL&text=ACIL&t=575&ask_summarization=1"},{"index":8,"title":"Matematik Problemleri Çözümü","list":{"type":"unordered","items":["6m6 sayısı m ile bölündüğünde bölüm iki basamaklı olduğuna göre, m sayısı 8 olmak zorunda ve kalan 6 olarak bulunur.","a8bc ve a3bc dört basamaklı iki sayıdır, a8bc sayısı 19'a bölündüğünde 3 kalanı verdiğine göre, a3bc 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