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Sınıf Konuları Oynatma Listesi İçin : https://bit.ly/3b7hfis ✨ TYT Fizik Kampı Oynatma Listesi İçin...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4312354/ca9187c81ee08fada1fbb819cc8b744d/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/xDPgHgIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"1","reqid":"1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=videoid:3164187367446589173","teaser":[{"list":{"type":"unordered","items":["Bu video, bir fizik öğretmeninin öğrencilere yönelik hazırladığı eğitim içeriğidir. Öğretmen, Ayşe ve Burak adlı öğrencilerle birlikte ders anlatmaktadır.","Video, fizik konularını iki ana bölümden oluşmaktadır. İlk bölümde güç enerjisi konusu ele alınmakta, ardından itme ve çizgisel momentum kavramları detaylı olarak açıklanmaktadır. Öğretmen, itme-tepki yasası, çizgisel momentum korunumu prensibi ve bunların günlük hayattan örneklerle (kuş-jeep, gemi, golf topu, okçuluk, buz pisti, su hortumu, silah-kurşun, top-gülle, roket) pekiştirilmektedir.","Videoda ayrıca itmenin vektörel bir büyüklük olduğu, yönünün önemi ve momentum problemlerinin farklı yöntemlerle çözülebileceği gösterilmektedir. Dersin sonunda öğretmen, yarın grafik incelemeleri yapacaklarını ve birkaç gün momentum konusunu devam ettireceklerini belirtmektedir."]},"endTime":2497,"title":"Fizik Dersi: Güç Enerjisi, İtme ve Çizgisel Momentum","beginTime":0}],"fullResult":[{"index":0,"title":"Yeni Yılların Başarılarla Dolması","list":{"type":"unordered","items":["Konuşmacı yeni yılın kutlu olmasını ve bu yılın ilk dersi olduğunu belirtiyor.","Öğrencilerin motivasyon ve tempo düşüklükleri olabileceğini ancak sorunların üzerine gittiğinde başarı elde edilebileceğini vurguluyor.","Kendisinin 2018-2017 yıllarında işi kurarken karşılaştığı sorunları ve bunların çözümünde geçen zamanı anlatıyor."]},"beginTime":1,"endTime":68,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1&ask_summarization=1"},{"index":1,"title":"Başarı İçin Gerekli Tutum","list":{"type":"unordered","items":["Emek verenin meyvelerini alabileceğini, ancak bu işin hızla olmayacağını ve deneyerek ilerleyebileceğini belirtiyor.","Öğrencilerin yoğun ders programı nedeniyle soru bankalarını hemen parçalamaları beklenmediğini, sadece onların işini kolaylaştırmaya çalıştıklarını söylüyor.","TYT Fizik Kampının 55-57 günde, AYT Fizik Kampının ise 2,5 ayda bittiğini, 2023'ün herkes için güzel olacağına inandığını ifade ediyor."]},"beginTime":68,"endTime":167,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=68&ask_summarization=1"},{"index":2,"title":"Fizik Sorusu Çözümü","list":{"type":"unordered","items":["Düşey kesiti verilen, farklı yüzeylerle kaplanmış bir ray üzerinde serbest bırakılan cismin duracağı noktayı bulma sorusunu çözüyor.","Soruda verilen sürtünme değerlerini kullanarak potansiyel enerjinin kinetik enerjiye dönüşmesi ve sonra ısıya dönüşmesini açıklıyor.","Kütle artırsa bile cismin duracağı noktanın değişmeyeceğini, çünkü sürtünme kuvvetinin de arttığını ve bu durumun sonucunda M noktasında duracağını belirtiyor."]},"beginTime":167,"endTime":355,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=167&ask_summarization=1"},{"index":3,"title":"İtme Momentum Konusuna Giriş","list":{"type":"unordered","items":["İtme ve momentum konusunun kolay ve rahat bir konu olduğunu, ilk iki sayfada temel bilgilerin verileceğini söylüyor.","Konunun Newton mekaniği ile ilişkili olduğunu ve bazen enerji konularıyla da kesiştiğini belirtiyor.","14 sayfa boyunca konuşacaklarını, zor kazanımlar olmadığını ve sayısal işlemlerin karmaşık olmayacağını ifade ediyor."]},"beginTime":355,"endTime":462,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=355&ask_summarization=1"},{"index":4,"title":"Çizgisel Momentum","list":{"type":"unordered","items":["Çizgisel momentum, bir cismin kütlesi ile hızının çarpımı olarak tanımlanır ve p harfi ile gösterilir (p = m × v).","Momentum vektörel bir büyüklüktür, kütlenin skaler, hızın ise vektörel olduğu için yön önemlidir.","Momentumun birimi kilogram metre bölü saniyedir ve pratikte \"kırk 'lık momentum\" gibi kısaltmalarla ifade edilir."]},"beginTime":481,"endTime":576,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=481&ask_summarization=1"},{"index":5,"title":"Momentumun Önemi","list":{"type":"unordered","items":["Çizgisel momentum büyük olan cisimleri durdurmak için uygulanması gereken kuvvet daha büyüktür.","Aynı hızda giden bir kuş ve bir araç, araçın momentumu daha büyük olduğu için duvara çarptığında duvarı yıkabilirken kuş durur.","Büyük gemiler karaya yaklaşmadan önce 15-20 km kala motorlarını durdururlar çünkü momentumu büyük olduğu için durması uzun sürer."]},"beginTime":576,"endTime":717,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=576&ask_summarization=1"},{"index":6,"title":"İtme Kavramı","list":{"type":"unordered","items":["İtme, bir cisme etki eden net kuvvet ile kuvvetin etki süresinin çarpımından oluşan fiziksel büyüklüktür (İ = F × Δt).","İtme, momentumdaki değişimdir ve hem büyüklük hem de yön değişimi olduğunda oluşur.","İtme kuvveti değil, kuvvetin uygulanma süresi ile çarpımıdır."]},"beginTime":717,"endTime":977,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=717&ask_summarization=1"},{"index":7,"title":"İtmenin Örnekleri","list":{"type":"unordered","items":["Tenis topu duvara çarptığında momentumu değişir, örneğin 10'luk momentumla gelen top 6'luk momentumla geri döner.","İtme hesaplanırken momentum değişimi (Δp = p_son - p_ilk) kullanılır ve vektörel hesaplama yapılır.","Bir cismin yönü değişse bile momentum değişimi vardır çünkü momentum vektörel bir büyüklüktür."]},"beginTime":977,"endTime":1221,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=977&ask_summarization=1"},{"index":8,"title":"İtme ve Çizgisel Momentum İlişkisi","list":{"type":"unordered","items":["İtme ile çizgisel momentum arasında bir ilişki kurulabilir: İtme = momentumdaki değişim (F × Δt = m × Δv).","Bu formül dinamikten gelmektedir ve F × a ilişkisinden türetilmiştir.","İtme kuvveti değil, ortalama kuvvetin temas süresi ile çarpımıdır."]},"beginTime":1256,"endTime":1322,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1256&ask_summarization=1"},{"index":9,"title":"İtme ve Momentum Örnekleri","list":{"type":"unordered","items":["Bir cisme itme uygulandığında, cismin çizgisel momentumu değişir; bu değişiklik yön veya sayısal olarak olabilir.","Golf topu örneğinde, 400 Newton kuvvetle 1 saniye temas süresiyle vurulduğunda, 2 kg ağırlığında top 2 m/s hızla hareket eder.","Okçuluk örneğinde, 300 Newton kuvvetle 1 saniye temas süresiyle vurulduğunda, 1 kg ağırlığında ok 3 m/s hızla ayrılır."]},"beginTime":1322,"endTime":1637,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1322&ask_summarization=1"},{"index":10,"title":"Momentum Değişimi Problemleri","list":{"type":"unordered","items":["Kütlesi 1 kg olan bir cisimde, 20 Newton kuvvet uygulandığında hız 2 m/s'den 17 m/s'ye yükselir.","Momentum değişimi 15 kg·m/s olduğunda, kuvvetin uygulanma süresi 0,75 saniye olarak hesaplanır.","Bu problem dinamik denklemlerle de çözülebilir, momentum ve dinamik yaklaşımları yakından ilişkilidir."]},"beginTime":1637,"endTime":1755,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1637&ask_summarization=1"},{"index":11,"title":"İtme Kuvveti Örneği","list":{"type":"unordered","items":["Bir kilogram kütleye sahip cisim, 5 m/s hızla yatay düzlemde 30 derece açıyla bir engeli çarpar ve aynı hızla yansımıştır.","İtme kuvveti, momentumun değişimine eşittir ve cismin momentumunun yönünün değişmesi itme kuvvetinin belirtilmesi için yeterlidir.","Cismin momentumunun büyüklüğü değişmemiş, sadece yönü değişmiştir; bu nedenle engelin cisme uyguladığı itme kuvveti 5 m/s büyüklüğündedir."]},"beginTime":1759,"endTime":1888,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1759&ask_summarization=1"},{"index":12,"title":"İtme Kuvveti Hesaplama","list":{"type":"unordered","items":["Bir kuleden yatay olarak fırlatılan 2 kilogram kütleli cisim, yere 3 saniyede düşmüştür.","İtme kuvveti, kuvvetin süreye çarpımına eşittir ve bu örnekte yerçekimi kuvvetinden (2 Newton) ve süreden (3 saniye) bahsedilmektedir.","İtme kuvveti hesaplanırken, birimlere bakarak formülleri hatırlamak önemlidir; Newton biriminde kuvvet, kilogram ve metre/saniye birimlerinde momentum kullanılır."]},"beginTime":1888,"endTime":1950,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1888&ask_summarization=1"},{"index":13,"title":"Çizgisel Momentum Korunumu","list":{"type":"unordered","items":["Çizgisel momentum korunumu, dış kuvvet etkisi olmayan bir sistemde iki veya daha fazla parçacık etkileşimi durumunda, sistemin toplam çizgisel momentumunun sabit kalmasını ifade eder.","Bir sistemin toplam çizgisel momentumu her zaman sistemin ilk çizgisel momentumuna eşittir ve bu duruma çizgisel momentum korunumu denir.","Çizgisel momentum korunumu, birbirini iten cisimler, çarpışan cisimler, kenetlenen cisimler ve iç patlama sonucu parçalanan cisimler için geçerlidir."]},"beginTime":1950,"endTime":2030,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1950&ask_summarization=1"},{"index":14,"title":"Çizgisel Momentum Korunumu Örnekleri","list":{"type":"unordered","items":["İki kişi buz pastında dururken, biri diğerini ittiğinde etki-tepki kuvvetleri oluşur ve bu kuvvetler eşit büyüklükte, zıt yönlüdür.","Başlangıçta toplam momentum sıfır olan sistemin, kendi içindeki etkileşimler sonucunda toplam momentum değişmez, sonda da sıfır kalır.","Günlük hayatta momentum korunumu örneği olarak hortum, silah, top güllesi ve roket gibi sistemlerde gözlemlenebilir; bir yönde momentum oluştuğunda, karşıt yönde eşit büyüklükte momentum oluşur."]},"beginTime":2030,"endTime":2333,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2030&ask_summarization=1"},{"index":15,"title":"Momentum Kavramı ve Örnek","list":{"type":"unordered","items":["Ayşe ve Burak, sürtünmesiz bir buz pistinde yan yana duruyor, Ayşe arkadaşı itti ve zıt yönlerde hareket ettiler.","Ayşe'nin kütlesi Burak'tan az olduğundan, ayrıldıktan sonra Ayşe'nin hızı Burak'ın hızından daha fazla oldu.","Toplam çizgisel momentum korundu, başlangıçta ve sonunda toplam momentum sıfırdır."]},"beginTime":2336,"endTime":2411,"href":"/video/preview/3164187367446589173?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2336&ask_summarization=1"},{"index":16,"title":"Momentum ve Etki-Tepki Yasası","list":{"type":"unordered","items":["Ayşe ve Burak birbirlerine uyguladıkları itme kuvvetlerinin büyüklükleri 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Eğitmen, İsmail Hoca ile birlikte çalışma odasında ders anlatmaktadır.","Videoda itme ve momentum konusu detaylı olarak ele alınmakta, toplam 30 momentum sorusunun çözümü yapılmaktadır. İçerikte esnek çarpışma, momentum korunumu, kinetik enerji, sürtünmesiz hareket ve itme kavramları gibi konular örnek sorular üzerinden açıklanmaktadır. Eğitmen, her soru için adım adım çözüm sunarak konuyu pekiştirmektedir.","Videoda trambolin zıplama, buz pateni gösterisi, okey sopası kullanımı gibi günlük hayattan örneklerle momentum ve itme kavramları açıklanmakta, ayrıca sürtünmesiz düzlemdeki cisimlerin çarpışma problemleri, esnek ve inelastsik çarpışmalar, momentum değişimleri ve itme kuvvetleri gibi konular ele alınmaktadır. Video, AYT sınavına hazırlanan öğrenciler için hazırlanmış kapsamlı bir eğitim kaynağıdır."]},"endTime":4109,"title":"AYT Fizik Full Tekrar Kampı: İtme ve Momentum Soru Çözümleri","beginTime":0}],"fullResult":[{"index":0,"title":"AYT Fizik Momentum Soru Çözümleri","list":{"type":"unordered","items":["Vip fizik YouTube kanalında AYT fizik full tekrar kampının yedinci gün ikinci videosu yayınlanıyor.","Bu videoda itme ve momentum konusunda 16 soru çözülecek, toplamda 30 momentum sorusu çözülecek.","Full tekrar kamp kitabının sayfa 53'te dokuzuncu sorudan itibaren devam edilecek."]},"beginTime":2,"endTime":42,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2&ask_summarization=1"},{"index":1,"title":"Momentum Sorusu Çözümü","list":{"type":"unordered","items":["Kütleleri 4m ve 2m olan cisimler arasında esnek bir yay konulmuş, cisimler birbirine doğru hareket ettirilerek yay sıkıştırılmış.","Cisimler esnemeyen ip ile birbirine bağlanıyor ve sistem duruyor, ip kesildikten sonra cisimler birbirine ters yönde fırlıyor.","Cisimlerin momentumları birbirini götürerek son momentumun sıfır olması gerekiyor, cisimlerin hızları oranı 2:1 olmalı."]},"beginTime":42,"endTime":131,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=42&ask_summarization=1"},{"index":2,"title":"Momentum Sorusu Analizi","list":{"type":"unordered","items":["Cisimlerin momentumları büyüklük olarak aynı, sadece yönleri farklı.","Cisimlerin kazandıkları kinetik enerjilerin toplamı yayı sıkıştırmak için yapılan işe eşit olmalı.","Sürtünmeler önemsiz olduğu için enerji kaybı olmuyor, yaydaki enerji cisimlere aktarılıyor."]},"beginTime":131,"endTime":246,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=131&ask_summarization=1"},{"index":3,"title":"Patlama Sorusu Çözümü","list":{"type":"unordered","items":["Sürtünmelerin önemsiz olduğu ortamda, yerden ve hızıyla eğik olarak fırlatılan cismin yörüngesi üzerindeki K noktasında iç patlama sonucu iki parçaya ayrılıyor.","Patlama olmasaydı kütle merkezi belirli bir yörünge izleyecekti, patlama olsa dahi sistemin kütle merkezi aynı yörünge üzerinde olur.","İki parça patlamadan hemen sonra yönlerinden hangileri gibi hareket etmiş olabilir sorusunun cevabı E şıkkı (2 ve 4 yönleri)."]},"beginTime":246,"endTime":373,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=246&ask_summarization=1"},{"index":4,"title":"Mermi ve Blok Sorusu","list":{"type":"unordered","items":["Sürtünmenin önemsiz olduğu ortamda hızı 400 olan, kütlesi 50 gram olan bir mermi, kütlesi 150 gram olan tahta bloğa saplanıyor.","Tahta blokta kütle kaybı olmadığına göre, mermi bloğa saplandığında esnek olmayan bir çarpışma gerçekleşiyor.","Mermi ve blok birlikte ortak bir hızla hareket edecekler."]},"beginTime":373,"endTime":420,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=373&ask_summarization=1"},{"index":5,"title":"Kinetik Enerji ve Yay Enerjisi","list":{"type":"unordered","items":["Ortak hızlı hareket eden cisimlerin toplam kütle çarpı hız karesi kadar kinetik enerjisi vardır.","Cisimler yayı sıkıştırarak enerjisini yaydaki esneklik potansiyel enerjisine aktarır.","Cisim durduğunda kinetik enerjisi sıfır olur ve tüm enerji yaydaki potansiyel enerjiye dönüşür."]},"beginTime":423,"endTime":491,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=423&ask_summarization=1"},{"index":6,"title":"Ortak Hız Hesaplama","list":{"type":"unordered","items":["Esnek olmayan çarpışmalarda momentum korunumu yasası uygulanır.","Mermi (50 g) 400 m/s hızla hareket ederken, 150 g'lik cisim duruyor ve çarpışma sonrası 200 g'lik bir sistem oluştururlar.","Ortak hız 100 m/s olarak hesaplanır."]},"beginTime":491,"endTime":598,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=491&ask_summarization=1"},{"index":7,"title":"Enerji Aktarımı","list":{"type":"unordered","items":["Ortak hız bulunduktan sonra kinetik enerji potansiyel enerjiye aktarılır.","Toplam kütle 200 g (0,2 kg) olduğundan, kinetik enerji hesaplamasında kilogram cinsinden kullanılır.","Hesaplamaya göre yaydaki potansiyel enerji 1000 joule olarak bulunur."]},"beginTime":598,"endTime":683,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=598&ask_summarization=1"},{"index":8,"title":"Özdeş Sarkaçlar ve Esnek Çarpışma","list":{"type":"unordered","items":["Özdeş kaleme sarkaçlarından biri (L) düşey açı yapacak kadar çekilip serbest bırakılır ve esnek olarak diğer sarkaca (M) çarpışır.","Kütleleri eşit olan esnek çarpışmalarda hız aktarılır, L'nin hızı M'ye aktarılır.","M, L'den aldığı hızla aynı açıyla yükselir çünkü enerji korunur."]},"beginTime":683,"endTime":810,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=683&ask_summarization=1"},{"index":9,"title":"Momentum Hesaplaması","list":{"type":"unordered","items":["L ve M sarkacının momentumları çarpışma öncesi ve sonrası incelenir.","L sarkacının momentumu çarpışma öncesi sağa doğru vektörel olarak ifade edilir.","Çarpışma sonrası L'nin momentumu sıfır olur, M'nin momentumu ise çarpışma öncesi L'nin momentumuna eşit olur."]},"beginTime":810,"endTime":859,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=810&ask_summarization=1"},{"index":10,"title":"Sürtünmesiz Yatay Düzlemdeki Çarpışma Problemi","list":{"type":"unordered","items":["Sürtünmelerin önemsenmediği yatay düzlemde hareket eden K ve L isimli cisimlerin konum-zaman grafikleri inceleniyor.","K cisminin hızı sola doğru -3 m/s, L cisminin hızı sağa doğru +1 m/s olarak belirleniyor.","Çarpışma sonrası K cisminin hızı sağa doğru +3 m/s, L cisminin hızı sola doğru -1 m/s olarak değişiyor."]},"beginTime":862,"endTime":1021,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=862&ask_summarization=1"},{"index":11,"title":"Çarpışma Sonuçları ve Momentum Analizi","list":{"type":"unordered","items":["Cisimler çarpışma sonrası geldikleri gibi dönmüşler, bu durum momentumları eşit büyüklükte olduğunu gösteriyor.","K cisminin kütlesi 1 kg, L cisminin kütlesi 3 kg olarak belirleniyor.","Çarpışma öncesi ve sonrası cisimlerin momentumları eşit büyüklüktedir, ancak yönleri farklıdır."]},"beginTime":1021,"endTime":1113,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1021&ask_summarization=1"},{"index":12,"title":"İtme ve Momentum Değişimi","list":{"type":"unordered","items":["L cisminin momentumu çarpışma sonrası değiştiği için etki eden toplam itme sıfır değildir.","L cisminin momentum değişimi vektörel olarak hesaplandığında sola doğru -6 kg·m/s olarak bulunuyor.","Cevaplar arasında doğru olanlar belirleniyor."]},"beginTime":1113,"endTime":1194,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1113&ask_summarization=1"},{"index":13,"title":"Düşey Hızla Fırlatılan Cisim Problemi","list":{"type":"unordered","items":["Sürtünmelerin önemsenmediği ve çekim ivmesinin olmadığı bir ortamda düşey hızla fırlatılan bir cisim yer ve tavana esnek çarpışma yapıyor.","Yer ve tavanın cisim üzerinde uyguladığı itmeler eşit büyüklüktedir, ancak yönleri farklıdır.","Yerin uyguladığı itme yukarı doğru, tavanın uyguladığı itme aşağı doğru olup, her ikisi de 2mv büyüklüğündedir."]},"beginTime":1194,"endTime":1469,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1194&ask_summarization=1"},{"index":14,"title":"Çarpışma Problemi Çözümü","list":{"type":"unordered","items":["Çarpışma öncesi ve sonrası cisimlerin konumları incelenerek, bir cismin hızının 3v, diğerinin hızının 2v olduğu belirleniyor.","Esnek çarpışmada kütleler eşit olduğunda hızlar birbirine aktarıldığı için, K cisminin çarpışma öncesi momentumu sağa doğru m×3v, L leğenin momentumu sola doğru m×2v olarak hesaplanıyor.","Çarpışma sonrası L leğenin kinetik enerjisi artmış, K cisminin momentum büyüklüğü azalmıştır."]},"beginTime":1482,"endTime":1703,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1482&ask_summarization=1"},{"index":15,"title":"Düşey Ray Sisteminde Çarpışma Problemi","list":{"type":"unordered","items":["Sürtünmelerin önemsenmediği düşey ray sisteminde, h yüksekliğinden bırakılan cisimler yere v hızıyla ulaşır.","İlk sistemde çarpışma sonrası cisimler sola doğru v/3 hızıyla hareket eder ve yükseklik 1/9h'ye çıkar.","İkinci sistemde çarpışma sonrası cisimler sağa doğru v/4 hızıyla hareket eder ve yükseklik h/16'ya çıkar, oran 9/16 olarak bulunur."]},"beginTime":1703,"endTime":2074,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1703&ask_summarization=1"},{"index":16,"title":"Momentum Hesaplama Problemi","list":{"type":"unordered","items":["Bloğa saplanan bilyeler, bloğun şeklini bozmadan blokla birlikte sürtünmesiz yatay zeminde hareket ederken, sistemin ilk momentumu ile son momentumu eşittir.","Her bilyenin kütlesi 1/2 ve hızı 2 olduğundan, her birinin momentumu 1'dir ve toplam momentum sağa doğru 3, aşağı doğru 2'dir.","Oyun hamuru (7 kg) yerin içine gidebilirken, aşağı doğru momentum yerin tepkisiyle yok olur ve çarpışma sonrası momentum sağa doğru 2 olur."]},"beginTime":2090,"endTime":2277,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2090&ask_summarization=1"},{"index":17,"title":"Top Çarpması Problemi","list":{"type":"unordered","items":["Kütleleri eşit olan yumuşak sünger top ve esnemeyen plastik top aynı yükseklikten sürtünmesiz ortamda bırakıldığında, yere aynı hızla çarparlar.","Sünger top zıplamadan durduğunda zemin yukarı doğru v*m kadarlık bir momentum itmesi uygular, plastik top ise yukarı doğru 2v*m kadarlık bir itme alır.","Zeminin toplara uyguladığı ortalama kuvvetler eşit büyüklüktedir, ancak sünger topun momentum değişimi 2v*m'dir."]},"beginTime":2277,"endTime":2611,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2277&ask_summarization=1"},{"index":18,"title":"Çarpışma Testi Problemi","list":{"type":"unordered","items":["Çarpışma testinde özdeş ve cansız mankenler emniyet kemerleri takılmadan sürücü koltuğuna yerleştirilir ve araçlar yatay yolda aynı hızla ilerlerken duvara çarpıp dururlar.","Kar aracının tamamen durma süresi, aracınınkinden daha büyüktür."]},"beginTime":2611,"endTime":2645,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2611&ask_summarization=1"},{"index":19,"title":"Çarpışma Sorununun Analizi","list":{"type":"unordered","items":["Çarpışmalar sırasında cansız mankenler araçlara göre hareketsiz kaldığı için, araç durduğunda manken de duruyor.","Mankenin kütlesine bakıldığında, araçlar sabit hızla giderken mankenin sola doğru momentumu var.","Mankenin durdurulması için duvar tarafından sağa doğru uygulanan itme gerekiyor."]},"beginTime":2646,"endTime":2736,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2646&ask_summarization=1"},{"index":20,"title":"İtme ve Kuvvet İlişkisi","list":{"type":"unordered","items":["K aracındaki cansız mankene etki eden ortalama kuvvet, L aracındaki mankene etki eden ortalama kuvvettense küçüktür.","İtme kuvvet çarpı zamandır ve iki mankene uygulanan itmeler eşit büyüklüktedir.","İtmeler eşit olduğundan, kuvvetlerin zamanları farklıdır; küçük kuvvete daha uzun süre uygulanır."]},"beginTime":2736,"endTime":2813,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2736&ask_summarization=1"},{"index":21,"title":"Doğru Cevapların Belirlenmesi","list":{"type":"unordered","items":["Çarpışma sırasında cansız mankenlere etki eden itmeler eşit büyüklüktedir.","K aracındaki cansız mankenin momentum değişiminin sıfır olması için itmenin sıfır olması gerekir.","K aracındaki mankenin ilk momentumu varken son momentumu sıfır olduğu için momentum değişimi sıfır değildir, bu nedenle bu ifade yanlıştır."]},"beginTime":2813,"endTime":2872,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2813&ask_summarization=1"},{"index":22,"title":"Vagon ve Trambolin Sorusu","list":{"type":"unordered","items":["Sürtünmesiz bir ortamda yatay raylar üzerinde sabit hızla ilerleyen vagonun üstünde trambolin yerleştirilmiş ve trambolin üstündeki çocuk vagona göre belirli bir miktarda hızlanarak yukarı doğru zıplıyor.","Vagona göre hareket edildiğinde, çocuğun zıplama hareketinde vagonun hızı da eklenir çünkü çocuk hareket eden bir vagonun içerisinden atlıyor.","Çocuk yukarı doğru zıplayarak trambolini aşağı doğru ittiğinde, vagonun hızı artmaz çünkü momentum korunur ve vagonun aşağı gitme şansı yoktur."]},"beginTime":2883,"endTime":3035,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=2883&ask_summarization=1"},{"index":23,"title":"Momentum Korunumu","list":{"type":"unordered","items":["Momentum korunumu, başlangıç ve son momentumların eşit olmasıyla gösterilir; vagon ve çocuğun başlangıç momentumu, çocuğun ve vagonun momentumlarının toplamı ile son momentum eşittir.","Çocuğun yukarı doğru zıplaması için vagonu aşağı doğru itmesi gerekir, ancak vagonun aşağı gitme şansı olmadığı için zeminin tepkisiyle bu itme birbirini götürür.","Çocuk, vagona göre atladığı için vagon bundan etkilenmez ve vagonun hızında değişme olmaz."]},"beginTime":3035,"endTime":3280,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=3035&ask_summarization=1"},{"index":24,"title":"Buz Pateni Gösterisi","list":{"type":"unordered","items":["Ahmet ve Fatma buz pateni gösterisi sırasında, Ahmet'in kütlesi 60 kg, Fatma'nın kütlesi 80 kg ve sabit hızlarla birbirlerine doğru hareket ederlerken esnek olmayan çarpışma yaparlar.","İlk momentum 300 (Ahmet'in momentumu) - 160 (Fatma'nın momentumu) = 140 olarak hesaplanır ve çarpışma sonrası birlikte 1 m/s hızla hareket ederler.","Çarpışma sonrası Ahmet'in momentumu azalır çünkü hızı 1 m/s olur ve momentumu 60 kg·m/s olur, Fatma'nın momentumu da 80 kg·m/s olur."]},"beginTime":3280,"endTime":3386,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=3280&ask_summarization=1"},{"index":25,"title":"İtmeler ve Momentum Korunumu","list":{"type":"unordered","items":["Ahmet ve Fatma'nın çarpışma sırasında birbirine uyguladıkları itmeler eşit büyüklüktedir, ancak yönleri farklıdır.","Sistemin momentumu korunur çünkü sağa doğru ne kadar bir itme varsa sola doğru da o kadar itme olduğu için bunlar birbirini götürür.","Buz okey sahasında antrenman yapan bir sporcu, sabit hızla hareket eden paka okey sopası ile sabit bir itme uygulayarak kaleden geçmeyi amaçlıyor."]},"beginTime":3386,"endTime":3470,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=3386&ask_summarization=1"},{"index":26,"title":"Momentum Değişimi Problemi","list":{"type":"unordered","items":["Bir cismin sağa doğru momentumu var ve yukarı doğru göndermek için sola ve yukarı doğru bir itme uygulanması gerekiyor.","İtmenin büyüklüğü ve yönü hesaplanırken, açı 30 derece olduğu için itmenin bileşenleri ı×cos30 ve ı×sin30 olarak hesaplanıyor.","İtmenin büyüklüğü 2ı olmalı ki sola doğru bileşeni ı olsun ve yukarı doğru bileşeni ı√3 olsun, böylece momentum değişimi sağlanır."]},"beginTime":3478,"endTime":3610,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=3478&ask_summarization=1"},{"index":27,"title":"Esnek Boru Problemi","list":{"type":"unordered","items":["Esnek bir borunun farklı şekillerinde cisimler fırlatılıp momentum değişimleri inceleniyor.","Momentum değişimi (Δp) son momentumdan ilk momentumu vektörel olarak çıkartarak hesaplanıyor.","Farklı durumlarda momentum değişimi hesaplanarak, büyüklük sıralaması E=0, M=√2ı, L=√3ı olarak bulunuyor ve cevap C şıkkı olarak belirleniyor."]},"beginTime":3610,"endTime":3787,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=3610&ask_summarization=1"},{"index":28,"title":"Otoyolda Araçlar Problemi","list":{"type":"unordered","items":["Doğrusal bir otoyolda kütleleri verilen tır, kamyonet ve otomobil sabit hızlarla hareket ediyor ve aynı anda fren yapmaya başlıyor.","İlk olarak tır duruyor, sonra kamyonet, en son otomobil duruyor.","Fren yapan araçların durmasını sağlayan ortalama kuvvetler arasındaki ilişki hesaplanarak, en büyük kuvvetin tırın üzerinde olduğu, en küçük kuvvetin ise otomobilin üzerinde olduğu bulunuyor ve cevap B şıkkı olarak belirleniyor."]},"beginTime":3787,"endTime":4055,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=3787&ask_summarization=1"},{"index":29,"title":"Video Kapanışı","list":{"type":"unordered","items":["Video uzun ve yorucu olmasına rağmen, öğrencilerin sınava kadar destek olmaya devam edileceği belirtiliyor.","Videoları çekmek zor olmasına rağmen, öğrencilerin yanınızda olmaya devam edileceği vurgulanıyor."]},"beginTime":4055,"endTime":4090,"href":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=4055&ask_summarization=1"}],"linkTemplate":"/video/preview/10018739718810712709?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"İtme ve momentum soru 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#aytfizik #yks Bu konu anlatım videosunda itme ve momentum ünitesinden kuvvet - zaman grafiğinin alanına bakarak çizgisel momentum - zaman grafiği çizilmiş, çizgisel momentum - zaman...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/776653/38553c86b97ebfff24ee0408f0b55ff3/564x318_1"},"target":"_self","position":"5","reqid":"1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=videoid:18060994932976467125","teaser":[{"list":{"type":"unordered","items":["Bu video, bir fizik öğretmeninin öğrencilere yönelik hazırladığı eğitim içeriğidir. Öğretmen, EMA adlı bir öğrenciyle diyaloglar halinde konuyu anlatmaktadır.","Video, itme ve çizgisel momentum kavramlarını temel alarak, kuvvet-zaman ve çizgisel momentum-zaman grafiklerinin nasıl çizileceğini ve bunların arasındaki ilişkiyi açıklamaktadır. Öğretmen, itmenin momentum değişimine eşit olduğunu, kuvvet-zaman grafiğinin altındaki alanın itmeyi, çizgisel momentum zaman grafiğinin eğiminin ise net kuvveti verdiğini detaylı şekilde anlatmaktadır.","Videoda ayrıca, itmenin vektörel bir büyüklük olduğu, itme ile momentum değişiminin aynı olduğu ancak son momentumların eşit olmayabileceği örneklerle açıklanmaktadır. İki farklı yöntemle (hız-zaman grafiği ve çizgisel momentum-zaman grafiği) aynı problem çözülerek, çizgisel momentum zaman grafiğinin eğiminin net kuvveti verdiğini göstermektedir. Video, çizgisel momentumun korunumu konusunun bir sonraki derste anlatılacağı bilgisiyle sonlanmaktadır."]},"endTime":1425,"title":"Fizik Dersi: İtme, Momentum ve Kuvvet-Zaman Grafiği","beginTime":0}],"fullResult":[{"index":0,"title":"İtme ve Momentum İlişkisi","list":{"type":"unordered","items":["Son derste itme ve çizgisel momentum kavramları öğrenilmiş, itmenin momentum değişimine eşit olduğu belirtilmiştir.","Bu derste itme ve momentum arasındaki ilişkiyi gösteren grafikler çizilecek ve momentumun korunumu incelenecektir."]},"beginTime":4,"endTime":25,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=4&ask_summarization=1"},{"index":1,"title":"Kuvvet ve Hareket Durumu","list":{"type":"unordered","items":["m kütleli bir cisim sağ tarafa doğru F kuvveti ile t süre boyunca çekildikten sonra, kuvvet ters yöne (eksi yöne) dönerek yine t süre boyunca etki edecektir.","Cisim başlangıçta duruyor ve sağ tarafa doğru F kuvvetine maruz kalınca hızlanmaya başlayıp belirli bir hıza ulaşacaktır.","T süre sonra kuvvet ters yöne döndüğünde cisim yavaşlamaya başlayıp en nihayetinde duracaktır."]},"beginTime":25,"endTime":86,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=25&ask_summarization=1"},{"index":2,"title":"Kuvvet-Zaman Grafiği","list":{"type":"unordered","items":["Sağ taraf artı yön, sol taraf eksi yön olarak belirlenmiştir.","Kuvvet-zaman grafiğinde başlangıçta sağ tarafa doğru sabit bir F kuvveti t süre boyunca etki etmiştir.","T anından sonra kuvvet ters yöne dönmüş ancak yine F kadar olup t süre boyunca etki etmiştir."]},"beginTime":86,"endTime":110,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=86&ask_summarization=1"},{"index":3,"title":"Çizgisel Momentum-Zaman Grafiği","list":{"type":"unordered","items":["Başlangıçta duran bir cismin çizgisel momentumu sıfırdır, hız arttıkça çizgisel momentum da düzgün artar.","Üzerindeki net kuvvet sabit olduğunda, cisim düzgün hızlanır ve çizgisel momentum da düzgün artar.","Kuvvet ters yönde döndüğünde cisim yavaşlar, hız düzgün azalır ve çizgisel momentum da düzgün azalır."]},"beginTime":112,"endTime":172,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=112&ask_summarization=1"},{"index":4,"title":"Kuvvet-Zaman ve Çizgisel Momentum-Zaman Grafiği İlişkisi","list":{"type":"unordered","items":["Kuvvet-zaman grafiğinin alanı itmeyi verirken, çizgisel momentum-zaman grafiğinin eğimi cisme etki eden net kuvveti verir.","Kuvvet-zaman grafiğinin altındaki alan, kısa kenar (F) ile uzun kenar (Δt) çarpımı olan itmeyi verir.","Negatif itme, cismin momentumunu azaltır ve itme bir vektör olduğundan yönü de önemlidir."]},"beginTime":172,"endTime":286,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=172&ask_summarization=1"},{"index":5,"title":"Momentum Değişimi ve İtme","list":{"type":"unordered","items":["Hareketin bütününe bakıldığında, başlangıçtaki momentumla son durumdaki momentum eşittir çünkü toplam itme sıfırdır.","Eksi itme her zaman yavaşlatıcı anlamına gelmez, yön anlamına gelir; negatif itme cismin ters yönde hızlanmasına neden olabilir.","İtme negatif olduğunda, cismin momentum değişimi azalma şeklinde olur."]},"beginTime":286,"endTime":386,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=286&ask_summarization=1"},{"index":6,"title":"Çizgisel Momentum-Zaman Grafiğinin Eğimi","list":{"type":"unordered","items":["Çizgisel momentum-zaman grafiğinin eğimi, momentumdaki değişim (Δp) bölü zamandaki değişim (Δt) olan net kuvveti verir.","Grafiğin eğimi sabitse, üzerindeki kuvvet de sabittir.","Grafiğin eğimi ters yönde döndüğünde, kuvvet de ters yönde ve sabit olur."]},"beginTime":386,"endTime":488,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=386&ask_summarization=1"},{"index":7,"title":"Örnek Problemin Çözümü","list":{"type":"unordered","items":["Sürtünmeden ihmal edildiği yatay düzlemde durmakta olan bir cisme etki eden kuvvetin zamana bağlı değişim grafiği verilmiştir.","Kuvvet-zaman grafiğinin alanı hesaplanarak itme büyüklüğü bulunur.","Toplam itme sıfır olduğunda, cismin çizgisel momentumu değişmez."]},"beginTime":488,"endTime":570,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=488&ask_summarization=1"},{"index":8,"title":"Kuvvet-Zaman Grafiği ve Hareket Analizi","list":{"type":"unordered","items":["Başlangıçta duran bir cisme pozitif yönde artan bir kuvvet etki ediyor, bu nedenle cisim hızlanıyor.","İki saniye sonra kuvvet azalmaya başlıyor, ancak cisim hala artı yönde kuvvete maruz kaldığı için hızlanmaya devam ediyor.","Dört saniye sonunda kuvvet ters yöne dönüyor ve sabit bir değer alıyor, bu nedenle cisim yavaşlayıp duruyor."]},"beginTime":571,"endTime":642,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=571&ask_summarization=1"},{"index":9,"title":"Momentum Kavramı ve Grafiği","list":{"type":"unordered","items":["Başlangıçta duran cismin çizgisel momentumu sıfırdır ve son durumda da sıfır olmak zorundadır çünkü çizgisel momentum değişmemek zorundadır.","Grafiğe göre toplam itme sıfır olduğundan, başlangıçtaki momentum ile sondaki momentum aynı olmalıdır.","Cismin en sonunda durduğu sonucuna varılır."]},"beginTime":642,"endTime":675,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=642&ask_summarization=1"},{"index":10,"title":"İkinci Kuvvet-Zaman Grafiği Analizi","list":{"type":"unordered","items":["Sürtünmelerin ihmal edildiği yatay düzlemde durmakta olan iki kilogram kütleli cisme uygulanan kuvvetin zamana bağlı grafiği inceleniyor.","Kuvvet-zaman grafiğinin alanları hesaplanarak itme değerleri bulunuyor: +20 N·s, +10 N·s ve -10 N·s.","Toplam itme pozitif olduğundan, cisim başlangıçta duruyor ve sağ tarafa doğru hızlanıyor."]},"beginTime":675,"endTime":761,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=675&ask_summarization=1"},{"index":11,"title":"Momentum ve Hız Grafiği Çizimi","list":{"type":"unordered","items":["Çizgisel momentum-zaman grafiği, kuvvet-zaman grafiğinin eğimine eşittir ve bu eğim kuvvet değerini verir.","Hız-zaman grafiği, çizgisel momentum-zaman grafiğinin aynısıdır çünkü çizgisel momentum kütle çarpı hızdır ve kütle sabittir.","Hız-zaman grafiğinde sayısal değerler değişir çünkü hız, çizgisel momentumun kütleye bölünmesiyle bulunur."]},"beginTime":761,"endTime":920,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=761&ask_summarization=1"},{"index":12,"title":"Kuvvet-Zaman Grafiği ve İtme","list":{"type":"unordered","items":["Sürtünmelerin önemsenmediği yatay düzlemde bulunan K ve L cisimlerine etki eden kuvvetlerin zamana bağlı değişim grafiği inceleniyor.","Kuvvet-zaman grafiğinin altında kalan alanlar itmeyi verir; mavi alan F×t, kırmızı alan ise 2F×t/2 = F×t olarak hesaplanıyor.","İtmeler vektörel büyüklük olduğu için yönleri de önemlidir; her iki cisim de pozitif itme alıyor."]},"beginTime":922,"endTime":985,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=922&ask_summarization=1"},{"index":13,"title":"Momentum Değişimi ve Son Momentum","list":{"type":"unordered","items":["Cisimlerin son momentumları eşit olmak zorunda değildir çünkü başlangıç momentumları bilinmemektedir.","İtme, ivme gibi sadece değişim miktarını gösterir, cismin nereye gittiğini veya hızlanıp yavaşladığını göstermez.","İtme formülü F=ma'dan türetilebilir, bu nedenle itme hakkında ivme hakkında düşündüğümüz gibi düşünebiliriz."]},"beginTime":985,"endTime":1166,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=985&ask_summarization=1"},{"index":14,"title":"Çizgisel Momentum-Zaman Grafiği","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemde bulunan bir cismin çizgisel momentum-zaman grafiği inceleniyor.","Çizgisel momentum m×v formülüyle hesaplanır ve kütle sabit olduğunda momentum değişimi hız değişimiyle doğrudur.","Momentum parabolik azalıyorsa, hız da parabolik azalır; momentum sabitse hız sabittir."]},"beginTime":1166,"endTime":1211,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1166&ask_summarization=1"},{"index":15,"title":"Hız-Zaman Grafiği Analizi","list":{"type":"unordered","items":["Hız-zaman grafiğinde eğim, ivmeyi verir ve sabit eğim sabit ivmeyi ifade eder.","T2-T3 zaman aralığında hız azaldığı için yavaşlama söz konusudur.","T2-T3 zaman aralığında hız sıfır değil, sabit hızla gidildiği için hız değeri vardır."]},"beginTime":1214,"endTime":1249,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1214&ask_summarization=1"},{"index":16,"title":"Net Kuvvet Analizi","list":{"type":"unordered","items":["2T-3T zaman aralığında hız azalan bir cismin ivmesi azalmaktadır.","Eğim hesaplandığında, teğetlerin gitgide düzleşmesi ivmenin azaldığını gösterir.","F=ma formülüne göre ivme azalıyorsa net kuvvet de azalmaktadır."]},"beginTime":1249,"endTime":1289,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1249&ask_summarization=1"},{"index":17,"title":"Çizgisel Momentum-Zaman Grafiği Analizi","list":{"type":"unordered","items":["Çizgisel momentum-zaman grafiğinin eğimi net kuvveti verir (Δp/Δt).","T-T2 zaman aralığında eğim sabit olduğundan net kuvvet sabittir ve cisim sabit ivmeyle yavaşlamaktadır.","T2-T3 zaman aralığında dümdüz bir çizgi olduğundan net kuvvet sıfırdır ve cisim sabit hızla gider."]},"beginTime":1289,"endTime":1397,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1289&ask_summarization=1"},{"index":18,"title":"Sonuç","list":{"type":"unordered","items":["Sorunun cevabı birinci ve üçüncü öncüllerdir.","Videonun devamında çizgisel momentumun korunumu anlatılacaktır."]},"beginTime":1397,"endTime":1411,"href":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1397&ask_summarization=1"}],"linkTemplate":"/video/preview/18060994932976467125?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Kuvvet - Zaman ve Çizgisel Momentum - Zaman Grafikleri | 88 Günde AYT Fizik Kampı | 22. 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📒📙50 Günde TYT Fizik Set 👉Trendyol : https://bit.ly/447dbf4 📹90 Günde AYT Fizik Kitap İncelemesi : • 90 Günde AYT Fizik Kampı | 0.Gün | 2024 Ta...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4825664/f18d001db5eb2d67459d063085bedd4c/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/jEZPQwIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"14","reqid":"1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=videoid:10234407424114306838","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan AYT fizik kampının 20. gününde itme ve momentum konusunu anlatan eğitim içeriğidir.","Video, itme ve momentum kavramlarının temel tanımlarından başlayarak, formüllerini ve uygulamalarını detaylı şekilde ele almaktadır. Eğitmen önce teorik bilgileri açıklamakta, ardından ÖSYM tadında sorular, bardakların farklı zeminlere düşmesi, golf topu ve otomobil çarpışma testi gibi örneklerle konuyu pekiştirmektedir. Ayrıca kuvvet-zaman, momentum-zaman ve momentum-hız grafikleri üzerinden itme ve momentum kavramlarını grafiksel olarak da anlatmaktadır.","Videoda yatay atış hareketi, düşey atış hareketi ve cisimlerin duvara çarpması gibi farklı senaryolarda momentum değişimi ve itme hesaplamaları örneklerle açıklanmakta, her soru için farklı çözüm yöntemleri sunulmaktadır. Video, öğrencilere konu anlatımı üç videosunun izlenmesi ve ödev olarak verilen test sorularının çözülmesi tavsiyesiyle sonlanmaktadır."]},"endTime":2769,"title":"AYT Fizik Kampı: İtme ve Momentum Konusu","beginTime":0}],"fullResult":[{"index":0,"title":"İtme ve Momentum Konusuna Giriş","list":{"type":"unordered","items":["AYT fizik kampının 20. gününde itme ve momentum konusuna başlanıyor.","İtme ve momentum, ÖSYM'nin en sevdiği konulardan biri olup AYT sınavında mutlaka soru geliyor.","Konu üç konu anlatımı ve iki soru çözümü olmak üzere beş video ile anlatılacak."]},"beginTime":5,"endTime":73,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=5&ask_summarization=1"},{"index":1,"title":"İtme Kavramı","list":{"type":"unordered","items":["Bir cismin hızını değiştirmek için cisme belirli bir süre kuvvet uygulanması gerekiyor.","İtme (impuls), kuvvet ile etki süresinin çarpımına denir ve formülü F×t'dir.","İtme vektörel bir büyüklüktür, birimi saniyedir ve kuvvet ile etki süresi doğru orantılıdır."]},"beginTime":73,"endTime":162,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=73&ask_summarization=1"},{"index":2,"title":"Momentum Kavramı","list":{"type":"unordered","items":["Momentum, bir cismin kütlesiyle hızının çarpımına denir ve formülü p=m×v'dir.","Momentum vektörel bir büyüklüktür, birimi kilogram metre bölü saniyedir.","Momentum, kütle ve hızın çarpımı olduğundan, kütlesi büyük olan cisimler daha büyük momentumlara sahiptir."]},"beginTime":162,"endTime":295,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=162&ask_summarization=1"},{"index":3,"title":"Momentum Değişimi","list":{"type":"unordered","items":["Momentum vektörel bir nicelik olduğu için momentum değişimi de vektöreldir.","Momentum değişimi, son momentumdan ilk momentumu vektörel olarak çıkartarak bulunur.","Momentum değişimi formülü m×(Δv) veya m×(son hız - ilk hız) şeklindedir."]},"beginTime":295,"endTime":431,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=295&ask_summarization=1"},{"index":4,"title":"İtme ve Momentum Değişimi İlişkisi","list":{"type":"unordered","items":["İtme, momentum değişimine eşittir çünkü F×Δt = m×Δv formülü itme ve momentum değişimi arasında ilişki kurar.","İtmenin yönü ile momentum değişiminin yönü her zaman aynıdır.","İtme ve momentum değişimi hem büyüklükleri hem de yönleri birbirine eşittir."]},"beginTime":431,"endTime":508,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=431&ask_summarization=1"},{"index":5,"title":"Bardak ve Zemindeki Çarpışma Problemi","list":{"type":"unordered","items":["ÖSYM tadında bir soru, iki sene önce AYT sınavında gelen sorunun birebir aynısıdır.","Soruda aynı yükseklikten sünger ve beton zemine bırakılan bardaklardan süngere düşen kırılmaz, ancak betona düşen kırılır.","Bardakların kütlesi ve ilk momentumu aynıdır, ancak çarpışma sonrası süngerde etki etme süresi uzun, betonda ise kısa olur."]},"beginTime":512,"endTime":619,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=512&ask_summarization=1"},{"index":6,"title":"Momentum Değişimi ve İtme Kuvveti","list":{"type":"unordered","items":["Momentum değişimi, son momentumdan ilk momentumu çıkartarak bulunur ve her iki durumda da yukarı doğru ve aynı büyüklüktedir.","Momentum değişimi itmeye eşittir, bu nedenle iki sistemin itmeleri de birbirine eşittir.","Süngerde etki etme süresi uzun olduğu için kuvvet küçük olur ve bardak kırılmaz, betonda ise etki etme süresi kısa olduğu için kuvvet büyük olur ve bardak kırılır."]},"beginTime":619,"endTime":865,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=619&ask_summarization=1"},{"index":7,"title":"Golf Topu Problemi","list":{"type":"unordered","items":["Kütlesi 200 gram olan topa ortalama 500 Newton büyüklüğünde kuvvetle vurulduğunda, etki süresi 0,1 saniye olduğunda oluşan itme 5 Newton saniye olur.","İtme, momentum değişimine eşittir ve momentum değişimi son momentumdan ilk momentumu çıkartarak bulunur.","Golf topunun başlangıç hızı sıfır olduğundan, son hızı 25 metre/saniye olarak hesaplanır."]},"beginTime":865,"endTime":980,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=865&ask_summarization=1"},{"index":8,"title":"Çarpışma Testi Problemi","list":{"type":"unordered","items":["108 km/saat sabit süratle giden otomobil duvara çarptığında 0,5 saniyede durabilmektedir.","Kütlesi 40 kilogram olan manken, direksiyonun kollarına uyguladığı tepki kuvveti, vücudunu etkileyen sürtünme kuvveti ve kemerin uyguladığı kuvvet yardımıyla durabilmektedir.","Mankenin otomobile göre hareketsiz kalabilmesi için ortalama itme kuvveti en az 1200 Newton olmalıdır."]},"beginTime":980,"endTime":1129,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=980&ask_summarization=1"},{"index":9,"title":"İtme ve Momentum Değişimi Problemi","list":{"type":"unordered","items":["İtme formülü F×Δt = Δp (momentum değişimi) kullanılarak, mankenin son hızının sıfır olduğu ve ilk hızının -30 m/s olduğu hesaplanıyor.","Mankenin kütlesi 40 kg olduğundan, itme değeri 1200 Newton saniye olarak bulunuyor ve bu değer sağa doğru bir itme anlamına geliyor.","Otomobilin 0,5 saniyede durduğu bilgisiyle ortalama kuvvet 2400 Newton olarak hesaplanıyor."]},"beginTime":1133,"endTime":1292,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1133&ask_summarization=1"},{"index":10,"title":"Yatay ve Düşey Momentum Değişimi","list":{"type":"unordered","items":["Kütlesi 2 kg olan bir cisim 45 metre yükseklikten yatay 20 m/s hızla fırlatılıyor ve yere düşene kadar yatay momentum değişimi sıfırdır çünkü yataydaki hız değişmiyor.","Düşeyde cisim 3 saniyede yere çakılıyor ve düşey hızı 30 m/s oluyor, bu nedenle düşey momentum değişimi 60 m olarak bulunuyor.","Sürtünmelerin olmadığı ortamda cisme etki eden tek kuvvet ağırlık olduğundan, itme değeri 60 Newton saniye olarak hesaplanıyor."]},"beginTime":1292,"endTime":1458,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1292&ask_summarization=1"},{"index":11,"title":"Duvarla Çarpışma Problemi","list":{"type":"unordered","items":["1 kg kütleli bir cisim duvara 20 m/s hızla çarpıyor ve kinetik enerjisinin %75'ini kaybederek geri yansıyor.","Cismin kinetik enerjisi 200 jul olduğundan, %75'ini kaybetmesi 50 jul kinetik enerji kalması anlamına geliyor ve bu durumda son hızı 10 m/s olarak bulunuyor.","Momentum değişimi 30 jul olarak hesaplanıyor ve duvarın cisme uyguladığı ortalama kuvvet 300 Newton olarak bulunuyor."]},"beginTime":1458,"endTime":1652,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1458&ask_summarization=1"},{"index":12,"title":"İtme ve Momentum Değişimi","list":{"type":"unordered","items":["İtme, momentum değişimi ile eşittir ve F×t formülüyle hesaplanamaz.","Momentum değişimi, son momentumdan ilk momentumu vektörel olarak çıkarmak demektir.","İki vektör eşitse ve aralarındaki açı 120 derece ise, sonuç vektör tam ortadan bir tanesidir."]},"beginTime":1654,"endTime":1758,"href":"/video/preview/10234407424114306838?parent-reqid=1765291208323325-4810130186209173280-balancer-l7leveler-kubr-yp-klg-36-BAL&text=ADRIAN+MOMENTUM&t=1654&ask_summarization=1"},{"index":13,"title":"İtme Hesaplama Örnekleri","list":{"type":"unordered","items":["İlk örnekte, K cismine etki eden itme 1mv kadardır.","İkinci örnekte, iki cisme etki eden itme 1,2mv kadardır.","Üçüncü örnekte, üçüncü cisme etki eden itme 1,60 mv 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