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fizik itme momentum korunum. ayt fizik momentum korunumu. itme ve momentum ayt fizik. 🎸Kimya Derslerimizi İzlemek İsterseniz : bit.ly/3eNmhli 🚀 Kimya Kitap + Video Paketler ve Fizik Adına...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/2301951/b2fa534c279d9f1f281b6cbd0c0b7422/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/NuCCHwIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"12","reqid":"1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=videoid:9274111755958896778","teaser":[{"list":{"type":"unordered","items":["Bu video, bir öğretmenin fizik dersinde momentum, patlama ve itme kuvveti konularını anlattığı eğitim içeriğidir. Öğretmen, öğrencilere hitap ederek konuyu açıklamakta ve çeşitli problem çözümleri yapmaktadır.","Videoda öncelikle patlama ve çatlama konusu ele alınmakta, ardından momentum kavramı üzerinden çeşitli problem çözümleri sunulmaktadır. Öğretmen, yatay düzlemde hareket eden cisimlerin patlaması, çarpışıp kenetlenen cisimlerin patlaması, drone parçalarının arasındaki uzaklık, serbest bırakılan cismin oyun hamuruna yapışması ve kaykay üzerinde duran kişinin topu fırlatması gibi farklı fizik problemlerini adım adım çözmektedir.","Video, sınav hazırlığı yapan öğrenciler için test soruları ve çözüm teknikleri içermekte, ayrıca momentum korunumu prensibi, net kuvvet sıfır olduğu durumlar ve fizik problemlerinde mantık çerçevesinde düşünmenin önemi vurgulanmaktadır. Video sonunda öğretmen, kendi drone kaybetme hikayesini anlatarak motivasyon vermektedir."]},"endTime":2242,"title":"Fizik Dersi: Momentum, Patlama ve İtme Kuvveti","beginTime":0}],"fullResult":[{"index":0,"title":"Patlama ve Çatlama Konusuna Giriş","list":{"type":"unordered","items":["Konu patlama ve çatlama konusuna gelmiş ve bugün bu konu bitirilecek.","Sınavda bu konu gelirse 30-35 saniyede rahat yapılabilir.","Emek veren, akıllı çalışan ve olanakları iyi kullanan insanlar kazanıyor."]},"beginTime":7,"endTime":120,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=7&ask_summarization=1"},{"index":1,"title":"Patlama ve Momentum Korunumu","list":{"type":"unordered","items":["Bir patlama ile çeşitli parçalara ayrıldığında ilk momentum ile parçaların her birinin momentum toplamı korunur.","Patlama sistemin kendi içinde olan bir etkidir ve dışarıdan bir etki yapmaz.","Patlama sonucunda enerji korunmaz çünkü ısı, ışık, ses gibi etmenler ortaya çıkar."]},"beginTime":120,"endTime":166,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=120&ask_summarization=1"},{"index":2,"title":"Patlama Örnekleri","list":{"type":"unordered","items":["Yatay ve sürtünmesiz düzlemde 30 m/s hızla hareket eden 5 kg'lık cisim iç patlama sonucu 2 kg ve 3 kg'lık iki parçaya ayrılıyor.","Patlama sonrası 3 kg kütleli cisim 80 m/s hızla hareket ettiğine göre, 2 kg kütleli cismin yönü ve hızının büyüklüğü 45 m/s olur.","Sürtünmelerin ihmal edildiği yatay düzlemde, kütlesi 1 kg olan K cismi ile kütlesi 3 kg olan L cismin çarpışıp kenetlenmesi ve iç patlama ile üç parçaya ayrılması durumunda, 2 kg kütleli parçanın hızının büyüklüğü hesaplanır."]},"beginTime":166,"endTime":365,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=166&ask_summarization=1"},{"index":3,"title":"Momentum Problemi Çözümü","list":{"type":"unordered","items":["İki parçanın momentumları hesaplanarak, sola doğru 10'luk bir momentum olduğu ve sağa doğru 30'luk bir momentuma ihtiyaç olduğu belirleniyor.","2 kilogramlık parçanın sağa doğru 15 metre/saniye hızla gitmesi gerektiği hesaplanıyor.","Düşeyde momentum olmadığı için, sola doğru 30'luk momentum, 2 kilogramlık parçanın 15 metre/saniye hızla hareket etmesiyle sağlanıyor."]},"beginTime":453,"endTime":542,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=453&ask_summarization=1"},{"index":4,"title":"Atış ve Momentum Problemi","list":{"type":"unordered","items":["50 metre/saniye ilk hızda atılan 4 kg kütleli cisim, 2 saniye sonra 1 kg ve 3 kg kütleli iki parçaya ayrılıyor.","Patlama öncesi cismin yukarı doğru 30 metre/saniyelik bir hız vektörü olduğu ve başlangıç momentumunun 120'lik olduğu hesaplanıyor.","1 kg kütleli parça serbest düşme yaptığı için momentumu sıfır, 3 kg kütleli parça ise yukarı doğru 40 metre/saniye hızla gitmesi gerekiyor."]},"beginTime":542,"endTime":813,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=542&ask_summarization=1"},{"index":5,"title":"Drone Kaybı Hikayesi","list":{"type":"unordered","items":["Konuşmacı, yurt dışından getirdiği drone'u Karaburun dağlarında uçururken sinyal kesildiğini ve drone'u kaybettiğini anlatıyor.","Drone'un kara kutu gibi bilgileri bir yere attığı ve bu bilgileri inceleyerek drone'un dağın üstünde kaybolduğunu tespit ettiğini belirtiyor.","15 gün boyunca arama kurtarma çalışmaları yapan konuşmacı, drone'u çalının içinde bulduğunu ve muhtemelen bir kuş saldırısı sonucu hasar aldığını söylüyor."]},"beginTime":813,"endTime":1231,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=813&ask_summarization=1"},{"index":6,"title":"Drone Parçalanma Problemi","list":{"type":"unordered","items":["Kütlesi 9 kg olan bir drone, yerden 45 metre yükseklikte havada sabit dururken içindeki birinin patlaması sonucu 3 kg ve 6 kg'lık iki parçaya ayrılıyor.","Parçalanma olayından hemen sonra yatay olarak fırlayan iki parçadan küçük olan parça, patladığı noktaya göre yatay olarak 6 metre uzaklığa düşüyor.","Büyük olan parçayla küçük olan parçalar arası yatay uzaklık 9 metredir."]},"beginTime":1234,"endTime":1525,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1234&ask_summarization=1"},{"index":7,"title":"Sürtünmeden İhmal Edilen Sistem Problemi","list":{"type":"unordered","items":["Sürtünmeden ihmal edildiği sistemde 20 metre yüksekliğinden serbest bırakan 2 kg kütleli bir cisim, önüne çıkan 1 kg kütleli iki tane oyun hamuruna yapışarak en fazla 5 metre yüksekliğe çıkıyor.","Cisim 20 metre yüksekliğinden serbest bırakıldığında 20 metre/saniye hızla hareket ediyor ve 40 kg momentum oluşturuyor.","Yapışma sonrası ortak kütle 4 kg oluyor ve 10 metre/saniye hızla hareket ederek 5 metre yüksekliğe çıkıyor."]},"beginTime":1525,"endTime":1700,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1525&ask_summarization=1"},{"index":8,"title":"Kaykay Üzerindeki Top Problemi","list":{"type":"unordered","items":["Kaykay üzerinde hareketsiz duran Can, elinde tuttuğu mavi topu yere göre belli bir hız büyüklüğünde yatay olarak fırlattığında topun izlediği yörünge inceleniyor.","Sistemin momentumu korunur, bu nedenle Can topu fırlattığında topun hareketine zıt yönde hareket edecektir.","Top Can'a göre daha büyük bir hızlanma ivmesi gösterecektir çünkü topun kütlesi daha az olduğu için aynı kuvvet altında daha büyük ivme alır."]},"beginTime":1700,"endTime":1828,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1700&ask_summarization=1"},{"index":9,"title":"Momentum ve İtme Kuvveti Problemi","list":{"type":"unordered","items":["Yatay ve sürtünmesiz bir ortamda 4 kg'lık bir cisim, 30 m/s hızla esnek ve doğal halde bulunan bir yaya çarpıp yaydan 15 m/s hızla ayrılmıştır.","Cismin yay ile etkileşim süresi 10 m/s olarak verilmiş ve yayın cismi uyguladığı ortalama itme kuvvetinin büyüklüğü sorulmuştur.","Cisim 120 m/s momentumla geliyor ve 15 m/s hızla ayrıldığında momentum değişimi 180 m/s olur, bu da itme kuvvetini gösterir."]},"beginTime":1832,"endTime":1953,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1832&ask_summarization=1"},{"index":10,"title":"Tekerlekli Sepet Problemi","list":{"type":"unordered","items":["Sürtünmelerin önemsiz olduğu bir ortamda 200 gram kütlesi olan bir macun, 10 m/s hızla yatay düzlemde durmakta olan 1800 gram kütleli tekerlekli sepetin içine fırlatılmıştır.","Macun tekerlekli sepetin içine yapıştığında sistemin ortak hızı sorulmuştur.","Yatayda momentum korunurken, düşeyde momentum korunmaz çünkü yapışma anında yerden gelen bir kuvvetle sönümlenir."]},"beginTime":1953,"endTime":2146,"href":"/video/preview/9274111755958896778?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1953&ask_summarization=1"},{"index":11,"title":"Konu Özeti ve Öneriler","list":{"type":"unordered","items":["Konu anlatımı basit sorularla değil, konunun özünü sorabilecekleri tarzda sorularla tamamlanmıştır.","Soruları çözerken kafada canlandırmak ve işlemlerin nedenini fizikçe açıklamak önemlidir.","Her adımında bir mantık çerçevesine oturtmak gerekir, kimsenin bilmediği detayları düşünmek yerine temel kavramları anlamak 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Ücretli soru çözümleri ve yardım için...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/3484021/6c3d99785cb61c098ce206af35307137/564x318_1"},"target":"_self","position":"14","reqid":"1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL","summary":{"fullTextUrl":"/int_search_summary?data=http%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3D-qp3vdagc1s","linkTemplate":"/video/preview/13953975847214205167?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Lineer Momentum ve İtme | Konu Anlatım | Üniversite Fiziği-1","related_orig_text":"Universe Momentum","related_porno":false,"related_less_3m_off":true,"client":"d2d","no_cnt":1,"related_src":"serp","related":"{\"porno\":false,\"vfp\":1,\"orig_text\":\"Universe Momentum\",\"url\":\"http:\\/\\/www.youtube.com\\/watch?v=-qp3vdagc1s\",\"src\":\"serp\",\"rvb\":\"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-AD4_vgFDgb8ARADFAH2AQAA4AP7Cwr8AgDn9fn5Cv8AAPIIAgj1AAAAC_wD_vb9AQAaAQT_-QAAABLsCfb7AAAA_Qv59v8BAAD6DQPvAgAAACAH-Pr_AAAA_gwJBPr_AAAVBfL4AQAAAPvjC_4AAAAAIAAtWhjBOzgTQAlITlACKnMQABpgMhEAYPIJ48D_CNvY-x0xB93rBffj5f808QDPLbmyBDffpy1E_yES7A-dAAAAB83V2xgAxn_Q2OEX1AgB0N4G_0tp8P8B_xgi4LvHcccgIBowJQAOAPYj-e4N6Zp7OvYQIAAtiyITOzgTQAlIb1ACKq8GEAwaoAYAALhBAAA0wgAAYEIAAKzCAAAAQAAAUEEAAJxCAAAgQQAA4MAAAKDBAADowQAAAMAAALDBAAAgQQAAoEEAAKBAAACIQQAAwEEAAIC_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-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-AAA8PgAAkj4AAOC8AADIvQAAVD4AAMg9AABwvQAAML0AAHC9AAD4vQAApj4AAJ4-AAB_PwAAUD0AAAw-AACIPQAANL4AADA9AACAOwAAmD0AAKi9AACCPgAA4DwAAIa-AACIvQAAuj4AAEC8AABUvgAAQLwAAFS-AADWvgAA6L0AAKC8AAD4vQAAbD4AAIK-AACiPgAAVL4AAAw-AAAQPQAAmL0AAN6-AAAQvQAAuL0AAHw-AACIvQAA2L0AAIA7AAAlPwAAur4AAOC8AABEPgAATL4AANi9AADIvQAAuL0gADgTQAlIfFABKo8CEAEagAIAAAy-AADGPgAAUL0AADe_AAD4vQAAUL0AANY-AAA8vgAAHD4AAIC7AAC4PQAAbL4AAGy-AADOvgAA2D0AABC9AAA0vgAABz8AANi9AACiPgAAmL0AAIq-AADYvQAAyL0AAHC9AABcvgAAHL4AAOg9AAAMvgAAor4AANg9AADYPQAA6L0AAIY-AAAsPgAANL4AAEw-AACaPgAAsr4AABA9AABcPgAAED0AAIA7AAAQvQAALL4AAHA9AAB_vwAA4DwAAMg9AACAOwAAqD0AAOA8AAA8PgAAcL0AAKg9AACYPQAAmL0AAMg9AABwvQAA4LwAAPi9AABAPAAAUL0AAJY-IAA4E0AJSHxQATAJOAFKAGAAaAA,\"}","related_url":"http://www.youtube.com/watch?v=-qp3vdagc1s","parent-reqid":"1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL","related_vfp":1,"relatedVideo":"yes"},"cwidth":1280,"cheight":720,"cratio":1.77777,"dups":["13953975847214205167"],"episode":0,"season":0,"isEmbedOnly":false,"greenHost":"YouTube","hasTranslation":true,"contentTypeId":null,"censored":false},"3129166226550969800":{"videoId":"3129166226550969800","docid":"34-0-8-Z64802D1799CB38C4","description":"11.Sınıf Fizik - İtme ve Momentum -3 | 2022 0:00 Videoda Neler Var? 0:13 Patlamalar 0:34 Durmakta Olan Bir Bombanın Patlaması 5:22 Hareketli Bir Cismin Patlaması Yeni videolar için ►...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/4012106/02241ffe0c472112f61a7eeecaa9ce79/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/bZUj1QEAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"15","reqid":"1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=videoid:3129166226550969800","teaser":[{"list":{"type":"unordered","items":["Bu video, bir fizik öğretmeninin momentum konusunu anlattığı eğitim içeriğidir. Öğretmen, öğrencilere hitap ederek konuyu adım adım açıklamaktadır.","Video, momentum korunumunun patlamalar ve çarpışmalar durumunda nasıl uygulandığını ele almaktadır. İçerikte durmakta olan ve hareketli cisimlerin iç patlamaları, sıkıştırılmış yay ve ip ile bağlı cisimlerin hareketleri, esnek olmayan çarpışmalar ve maksimum yüksekliğe ulaşan cismin iç patlama sonucu iki eşit parçaya ayrılması gibi çeşitli problem türleri incelenmektedir.","Videoda momentum korunumunun vektörel bir büyüklük olduğu vurgulanmakta, x ve y eksenlerinde momentum korunumunu hesaplama yöntemleri gösterilmekte ve her problem için detaylı hesaplamalar yapılmaktadır. Video, momentum konusunun sonuna gelindiği ve gelecek videolarda momentum ile ilgili soru çözümlerinin yapılacağı bilgisiyle sonlanmaktadır."]},"endTime":1572,"title":"Fizik Dersi: Momentum Korunumu ve Çarpışma Problemleri","beginTime":0}],"fullResult":[{"index":0,"title":"Momentum Korunumu ve Patlamalar","list":{"type":"unordered","items":["Momentum, herhangi bir dış etki veya sürtünme olmadığı sürece korunur; çarpışmadan önceki momentum çarpışmadan sonraki momentuma eşittir.","Bu videoda momentum korunumunun gerçekleştiği patlamalar konusu incelenecektir."]},"beginTime":0,"endTime":35,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=0&ask_summarization=1"},{"index":1,"title":"Durmakta Olan Cismin İç Patlaması","list":{"type":"unordered","items":["Durmakta olan bir cismin iç patlama sonucu parçalara ayrılması durumunda, patlamadan önce momentum sıfırdır çünkü cisim durmaktadır.","Patlamadan sonra parçalar farklı hızlarda hareket eder ve momentum vektörel bir büyüklük olduğundan, parçaların momentum vektörleri toplandığında başlangıç noktasına geri dönülür.","Momentum korunumu, x ve y eksenlerinde ayrı ayrı da incelenebilir; sola giden parçalara artı, sağa giden parçalara eksi değer verilir."]},"beginTime":35,"endTime":223,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=35&ask_summarization=1"},{"index":2,"title":"Örnek Soru Çözümü","list":{"type":"unordered","items":["Durmakta olan 6 kilogram kütleli bir cisim iç patlama sonucu eşit kütleli üç parçaya ayrılır ve parçaların hızları verildiğinde, üçüncü parçanın hızı hesaplanabilir.","Vektörel toplama yöntemi kullanılarak, parçaların momentum vektörleri toplanır ve üçüncü parçanın hızı 20 m/s olarak 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eşit parçaya ayrılır.","Patlamadan önceki momentum, cismin kütlesi ve hızıyla hesaplanır.","Patlamadan sonraki momentum vektörleri toplanarak, parçaların hızları ve hareket yönleri bulunur."]},"beginTime":411,"endTime":528,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=411&ask_summarization=1"},{"index":5,"title":"Momentum Korunumu Problemi","list":{"type":"unordered","items":["Bir kilogram kütlesinin hızı 20 m/s ve 53 derecelik açıda hareket ettiği belirtiliyor.","Patlama sonrası cismin hızı 10 m/s olarak hesaplanıyor ve momentumu 30 m·s olarak bulunuyor.","Momentum korunumu prensibi kullanılarak, diğer bir kilogram kütlesinin hızının 10 m/s olduğu ve yönünün aşağı doğru olduğu belirleniyor."]},"beginTime":544,"endTime":691,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=544&ask_summarization=1"},{"index":6,"title":"Yay ve İp Problemi","list":{"type":"unordered","items":["Sıkıştırılmış bir yay ve ip ile dengede olan cisimler, ip kesildiğinde fırlayacak.","Başlangıçta durdukları için momentumları sıfır olacak ve hız büyüklükleri arasında 3v = v ilişkisi olacak.","Momentum vektörel bir büyüklük olduğundan, cisimler zıt yönlere gittiği için momentumları eşit olmayacak, ancak kinetik enerjileri eşit olmayacak."]},"beginTime":691,"endTime":774,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=691&ask_summarization=1"},{"index":7,"title":"Esnek Olmayan Çarpışma Problemi","list":{"type":"unordered","items":["Sürtünmesiz düzlemde hızları ve kütleleri verilen cisimler çarpışıp yayı sıkıştırıyor.","Esnek olmayan çarpışmada momentum korunur ve cisimlerin birlikte hareket ederkenki hızı 7 m/s olarak hesaplanıyor.","Kinetik enerji korunmuyor, kaybedilen enerji yayda biriken potansiyel enerjiye dönüşüyor ve yaydaki sıkışma miktarı 10 cm olarak bulunuyor."]},"beginTime":774,"endTime":1019,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=774&ask_summarization=1"},{"index":8,"title":"İç Patlama Problemi","list":{"type":"unordered","items":["Sürtünmesiz ortamda atılan cisim maksimum yüksekliğe ulaştığında iç patlama sonucu iki eşit parçaya ayrılıyor.","Maksimum yüksekliğe ulaştığında cismin hızı sıfır olduğu için momentumu da sıfır olacak şekilde hareket doğrultuları seçilmeli.","Eşit kütlelere ayrılan parçaların momentumları birbirini sıfırlayacak şekilde hareket etmeleri gerekiyor."]},"beginTime":1019,"endTime":1121,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1019&ask_summarization=1"},{"index":9,"title":"Momentum Korunumu ve Enerji Korunumu Problemi","list":{"type":"unordered","items":["Momentum korunumu ve enerji korunumu prensipleriyle, sürtünmesi önemsiz bir düzenekte en kütleli mermi büyük m kütleli tahta blokla çarpışıp saplanıyor.","Esnek olmayan çarpışma durumunda, momentum korunumu denklemi kurularak ortak hız bulunuyor ve enerji korunumu denklemi ile potansiyel enerji hesaplanıyor.","H yüksekliği, yerçekimi ivmesine ve ortak hızına bağlı olarak hesaplanıyor."]},"beginTime":1126,"endTime":1255,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1126&ask_summarization=1"},{"index":10,"title":"Esnek Olmayan Çarpışma Problemi","list":{"type":"unordered","items":["Kütleleri 1 kg ve 2 kg olan iki cisim, 3 m/s ve 6 m/s hızlarla hareket ederek merkezi esnek olmayan çarpışma yapıyor ve beraber hareket ediyorlar.","Momentum korunumu denklemi kurularak çarpışma sonrası cisimlerin ortak hızının büyüklüğü 3 m/s olarak bulunuyor."]},"beginTime":1255,"endTime":1314,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1255&ask_summarization=1"},{"index":11,"title":"Arabaya Yapışan Cisim Problemi","list":{"type":"unordered","items":["6 kg kütleli bir araba 4 m/s hızla giderken, 2 kg kütleli bir cisim arabaya yapışıyor.","Momentum korunumu denklemi kurularak arabanın çarpışma sonrasındaki hızı 3 m/s olarak hesaplanıyor."]},"beginTime":1314,"endTime":1395,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1314&ask_summarization=1"},{"index":12,"title":"İki Mermi Çarpışması Problemi","list":{"type":"unordered","items":["Durmakta olan 8 kg kütleli bir bloğa hem kütleli iki mermi aynı anda çarpıp saplanıyor.","Momentum korunumu denklemi kurularak bloğun hangi yönde kaç m/s hızla harekete geçeceği hesaplanıyor.","Blok sol tarafa doğru 4 m/s hızla harekete geçiyor."]},"beginTime":1395,"endTime":1457,"href":"/video/preview/3129166226550969800?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1395&ask_summarization=1"},{"index":13,"title":"İtme ve Hız Problemi","list":{"type":"unordered","items":["Kütlesi 3 kg olan bir cisim, hızıyla fırlatıldığında etki eden itmenin büyüklüğü 180 Newton çarpı saniye oluyor.","İtme formülü 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ve Momentum Konu anlatımı ÖSYM (Yumurta) Sorusunun Çözümü. Güncel Hayat Uygulamaları PDF İndirmek İçin: https://drive.google.com/file/d/1Vr70...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/3852559/ee68a9aa7e91940b30e415bd2fc550a3/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/IZhRHwIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"16","reqid":"1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=videoid:2891256538286596933","teaser":[{"list":{"type":"unordered","items":["Bu video, bir eğitmen tarafından sunulan fizik dersidir. Eğitmen, öğrencilere hitap ederek itme ve momentum kavramlarını detaylı bir şekilde anlatmaktadır.","Video, itme kavramının tanımı (itme = F × Δt) ve birimleriyle başlayıp, momentum kavramını (momentum = m × v) açıklamaktadır. Ardından itme ile momentum arasındaki ilişki (itme = momentum değişimi) formülleri (F×t = Δp) anlatılmakta ve çeşitli örneklerle pekiştirilmektedir. Eğitmen, yatay ve düşey düzlemdeki momentum değişimlerini, çarpışma durumlarını ve duvarın cisme uyguladığı itmeleri hesaplamaktadır.","Videoda ayrıca etkileşim süresinin arttıkça cisme etki eden kuvvetin azaldığı açıklanmakta ve bunun günlük hayattaki uygulamaları (hava yastığı, diz bükme, yumurta düşme örnekleri) anlatılmaktadır. ÖSYM'de çıkan benzer sorular üzerinden konu pekiştirilmektedir."]},"endTime":1119,"title":"Fizik Dersi: İtme ve Momentum","beginTime":0}],"fullResult":[{"index":0,"title":"İtme Kavramı","list":{"type":"unordered","items":["İtme, kuvvetin cisim üzerinde yaptığı değişiklik kuvvetin etkime süresi ile orantılıdır.","İtme formülü İ = F × Δt'dir, burada F kuvvet (Newton), Δt zaman (saniye) ve İ itme (Newton-saniye) birimleridir.","İtme vektörel bir büyüklüktür ve kuvvetin yönüyle aynı yönlüdür."]},"beginTime":4,"endTime":51,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=4&ask_summarization=1"},{"index":1,"title":"İtme Örneği","list":{"type":"unordered","items":["Yatay fırlatan 3 kg kütleli cisme hareketi boyunca etkileyen itme, cismin ağırlığından (30 N) ve düşme süresinden (4 saniye) hesaplanarak 120 N-saniye olarak bulunur.","İtme, momentum değişimine eşittir: İ = Δp = m × Δv.","İtme momentum değişimine eşit olduğu için, yatay hız değişmediği için itme yoktur, düşeyde hız değiştiği için itme vardır."]},"beginTime":51,"endTime":137,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=51&ask_summarization=1"},{"index":2,"title":"Momentum Kavramı","list":{"type":"unordered","items":["Bir cismin kütlesi ile hızının çarpımına o cismin momentumu denir ve p ile gösterilir.","Momentum vektörel bir büyüklüktür ve birimi kilogram-metre/saniyedir.","İtme momentum değişimine eşittir: İ = Δp = m × Δv."]},"beginTime":137,"endTime":253,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=137&ask_summarization=1"},{"index":3,"title":"İtme ve Momentum İlişkisi","list":{"type":"unordered","items":["Yatayda momentum değişmediği için itme yoktur, düşeyde momentum değişimi vardır.","İtme momentum değişimine eşit olduğu için, sadece düşey düzleme göre itme işlemi yapılabilir.","Yatayda hız değişmediği için itme yoktur, kuvvet yoktur; düşeyde hız değiştiği için itme vardır, kuvvet vardır, momentum değişimi vardır."]},"beginTime":253,"endTime":388,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=253&ask_summarization=1"},{"index":4,"title":"İtme Örnekleri","list":{"type":"unordered","items":["Sürtünmesiz ortamda 4 kg kütleli bir cisim 500 metre yükseklikten serbest bırakıldığında, yere çarpınca geçen sürede cisme etken itme 40 N-saniye olarak bulunur.","İtme momentum değişimine eşit olduğu için, ilk hız verilmiş ve t = 10 saniye bulunmuşsa, hız 100 m/s olur ve itme 40 N-saniye olarak hesaplanır.","Duvarın cisme uyguladığı itme, momentum değişimi formülüyle hesaplanabilir ve vektörel toplama yapılarak bulunabilir."]},"beginTime":388,"endTime":759,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=388&ask_summarization=1"},{"index":5,"title":"İtme ve Momentum Değişimi","list":{"type":"unordered","items":["İtme, momentum değişimine eşittir ve vektörel olarak P-P şeklinde ifade edilir.","İtme değeri, m çarpı v formülüyle hesaplanır ve vektörel olarak yön bilgisi önemlidir.","İtme değeri, kuvvet çarpı zaman formülüyle de hesaplanabilir."]},"beginTime":766,"endTime":865,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=766&ask_summarization=1"},{"index":6,"title":"Etkileşim Süresi ve Kuvvet İlişkisi","list":{"type":"unordered","items":["Etkileşim süresi arttıkça cisme etki eden kuvvet azalır.","Esnek yapılar (sünger kaplı duvar) etkileşim süresini artırır ve cisme daha az kuvvet etki eder.","Kaza esnasında tamponun ezilmesi veya hava yastığının açılması, yolcu ile araba arasındaki etkileşim süresini artırarak kuvveti azaltır."]},"beginTime":865,"endTime":927,"href":"/video/preview/2891256538286596933?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=865&ask_summarization=1"},{"index":7,"title":"Etkileşim Süresi Örnekleri","list":{"type":"unordered","items":["Yere düşerken dizleri bükmek, yer ile aramızdaki etkileşim süresini artırarak etki eden kuvveti azaltır.","Yumuşak zemine düşen yumurta, yer ile etkileşim süresi arttığından dolayı daha az zarar görür ve kırılmayabilir.","Sert zemine düşen yumurta, etkileşim süresi kısa olduğu için büyük kuvvet etki eder ve 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İçerik, iki boyutta çarpışmalar, eşit kütleli cisimlerin çarpışmalarındaki özel durumlar, momentum korunumu prensibi, patlama olayları ve roketlerde momentum korunumu gibi konuları kapsamaktadır. Öğretmen, her konuyu adım adım açıklamakta ve çeşitli problem çözümleriyle konuyu pekiştirmektedir.","Video, 93-95 sayfalar arasındaki konuları kapsamakta olup, öğrencilere test ödevleri için hazırlanmıştır. İçerikte araba, kayık, roket gibi farklı fizik problemleri üzerinden momentum korunumu prensibinin uygulamaları gösterilmekte ve Pisagor bağıntısı gibi matematiksel yöntemler kullanılarak özel durumlar ispatlanmaktadır."]},"endTime":3372,"title":"İtme ve Momentum Dersi: Çarpışmalar ve Patlamalar","beginTime":0}],"fullResult":[{"index":0,"title":"İtme ve Momentum Dersinin Tanıtımı","list":{"type":"unordered","items":["Bu videoda iki boyutta çarpışmalar ve patlamalar öğretilerek itme ve momentum konusu tamamlanacak.","Dersin sonunda iki veya üç test ödevi verilecek ve bir sonraki videoda iki test çözümü paylaşılacak.","Ders kitabının 93 ile 95. sayfaları arasında bu konu işlenecek."]},"beginTime":50,"endTime":87,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=50&ask_summarization=1"},{"index":1,"title":"İki Boyutta Merkezi Olmayan Esnek Çarpışma","list":{"type":"unordered","items":["Merkezi olmayan çarpışmada cisimler belirli bir açıyla çarpıştığı için çarpışma sonrası saçılma hareketi oluyor.","Bu çarpışmada hem momentum hem de enerji korunuyor, ancak momentum iki boyutta (x ve y ekseninde) korunuyor.","Çarpışma öncesinde x eksenindeki momentum, çarpışma sonrasında da x ekseninde aynı momentum olmalı; y ekseninde de benzer şekilde momentum korunmalı."]},"beginTime":87,"endTime":199,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=87&ask_summarization=1"},{"index":2,"title":"Momentum Korunumu Uygulaması","list":{"type":"unordered","items":["Çarpışma öncesi momentum, cisimlerin kütlesi ve hızlarının çarpımlarıyla hesaplanır ve x ekseninde toplanır.","Çarpışma sonrası momentum, cisimlerin bileşenlerine ayrılmasıyla hesaplanır; bu bileşenler kosinüs ve sinüs fonksiyonları kullanılarak bulunur.","Momentum korunumu için çarpışma öncesi ve sonrası momentumlar eşitlenir; x eksenindeki değerler birbirine, y eksenindeki değerler birbirine eşitlenir."]},"beginTime":199,"endTime":433,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=199&ask_summarization=1"},{"index":3,"title":"Enerji Korunumu","list":{"type":"unordered","items":["Çarpışma öncesindeki cisimlerin kinetik enerjilerinin toplamı, çarpışma sonrası cisimlerin kinetik enerjilerinin toplamına eşittir.","Enerji skaler bir kavram olduğu için vektör işaretleri kullanılmaz."]},"beginTime":433,"endTime":453,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=433&ask_summarization=1"},{"index":4,"title":"Eşit Kütleli Cisimlerin Çarpışma Özel Durumu","list":{"type":"unordered","items":["Özel durumlar fizik problemlerinde işlem yapmaya gerek kalmadan cevabı vermemizi sağlar.","Eşit kütleli cisimlerden biri durgun, diğeri belirli bir hızla gelip çarpıştığında, çarpışma sonrasında cisimlerin saçılma açıları 90 derece olur.","Bu özel durumun ispatı Pisagor bağıntısı kullanılarak yapılır."]},"beginTime":456,"endTime":513,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=456&ask_summarization=1"},{"index":5,"title":"Pisagor Bağıntısından Gelen İspat","list":{"type":"unordered","items":["Çarpışma öncesi ve sonrası momentumlar arasındaki ilişki, enerji korunumu prensibiyle ifade edilir: p_x²/2 + p_y²/2 = p_x'²/2 + p_y'²/2.","Kütleler eşit olduğunda denklem sadeleştirilir ve p_x'² + p_y'² = p_x² bağıntısı elde edilir.","Pisagor bağıntısına göre, iki dik kenarın kareleri toplamı hipotenüsün karesine eşit olduğundan, p_x' ve p_y' momentumları birbirine dik olmalıdır."]},"beginTime":513,"endTime":662,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=513&ask_summarization=1"},{"index":6,"title":"Momentum Korunumu ve Özel Durum","list":{"type":"unordered","items":["Momentum korunumu prensibine göre, çarpışma öncesi momentum (2) çarpışma sonrası momentumların toplamına eşit olmalıdır.","p_y' ve p_x' momentumlarının toplamı, çarpışma öncesi momentumu verir ve bu momentumlar birbirine dik olur.","Eşit kütleli cisimlerden biri duruyor, diğeri çarptığında saçılma açıları 90 derece olur."]},"beginTime":662,"endTime":735,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=662&ask_summarization=1"},{"index":7,"title":"İkinci Özel Durum","list":{"type":"unordered","items":["Eşit kütleli cisimler birbirine 90 derecelik açıyla gelip çarparlarsa, çarpışma sonrasında saçılma açıları da 90 derece olur.","Bu özel durum da Pisagor bağıntısı kullanılarak ispatlanır.","Bu özel durumlar sorularda kullanılır ve örnek problemlerde uygulanabilir."]},"beginTime":735,"endTime":896,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=735&ask_summarization=1"},{"index":8,"title":"Momentum Bileşenlerinin Hesaplanması","list":{"type":"unordered","items":["Çarpışma sonrası momentum bileşenlerine ayrılırken, momentumun iki bileşeni vardır: sağa doğru ve yukarı doğru.","Momentumun sağa doğru bileşeni 3e × cos53° = 1,8e, yukarı doğru bileşeni ise 3e × sin53° = 2,4e olarak hesaplanır.","İkinci cismin momentumu 2e × cos37° = 1,6e (sağa doğru) ve 2e × sin37° = 0,8e (aşağı doğru) olarak hesaplanır."]},"beginTime":899,"endTime":1000,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=899&ask_summarization=1"},{"index":9,"title":"Çarpışma Öncesi ve Sonrası Momentum Denge","list":{"type":"unordered","items":["Çarpışma öncesi yukarı ve aşağı momentumunun sıfır olması gerektiğinden, yukarı ve aşağı momentumlar eşit olmalıdır.","Eşitlikten v₂ = 4 m/s bulunur, ardından v₁ = 5 m/s olarak hesaplanır.","Çarpışma öncesi ve sonrası momentumların eşit olması gerekir."]},"beginTime":1000,"endTime":1082,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1000&ask_summarization=1"},{"index":10,"title":"Eşit Kütleye Sahip Cisimlerin Çarpışması","list":{"type":"unordered","items":["Eşit kütleye sahip cisimler çarpıştığında, çarpışma sonrasında 90 derece açı ile saçılır.","Çarpışma öncesi momentum, çarpışma sonrası momentumla eşit olmalıdır.","P cismi sola doğru 2 m/s hızla, R cismi ise sağa doğru 1 m/s ve aşağı doğru 1 m/s hızla hareket edecektir."]},"beginTime":1082,"endTime":1299,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1082&ask_summarization=1"},{"index":11,"title":"Tam Esnek Olmayan Çarpışma","list":{"type":"unordered","items":["Tam esnek olmayan çarpışmada cisimler çarpıştıktan sonra birbirine yapışır.","Cisimler çarpıştıktan sonra belirli bir noktaya doğru hareket eder.","Cisimlerin kütleleri oranı sorulmaktadır."]},"beginTime":1299,"endTime":1324,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1299&ask_summarization=1"},{"index":12,"title":"Çarpışma Problemi Çözümü","list":{"type":"unordered","items":["Çarpışma sonrası momentum, sağa doğru iki p ve aşağı doğru p değerlerine sahip olacak.","Çarpışma öncesi momentum, sağa doğru em iki ve iki ile aşağı doğru m bir ve bir değerlerinden oluşuyor.","Çarpışma öncesi ve sonrası momentumların eşit olması gereği, m iki/m bir oranı 3 olarak bulunuyor."]},"beginTime":1327,"endTime":1469,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1327&ask_summarization=1"},{"index":13,"title":"Yapışan Cisimler Problemi","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemde kütleleri 4 ve 6 olan cisimler çarpışarak yapışıyor.","Çarpışma öncesi cisimlerin momentumları toplamı, çarpışma sonrası ortak cismin momentumuna eşit olmalı.","Ortak cismin hızının büyüklüğü 5 metre/saniye olarak hesaplanıyor."]},"beginTime":1469,"endTime":1606,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1469&ask_summarization=1"},{"index":14,"title":"Patlama Olayları","list":{"type":"unordered","items":["Patlama olayında kimyasal enerji kinetik enerjiye dönüşebilir, örneğin bomba patlaması durumunda.","Patlama olayında dışarıdan etki eden bir kuvvet olmadığı için momentum korunur.","Patlamalarda sistemin kütle merkezi korunur, patlama olmasaydı kütle merkezinin neresi olacağını biliyorsak, patlama olduğunda da kütle merkezinin orası olur."]},"beginTime":1606,"endTime":1934,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1606&ask_summarization=1"},{"index":15,"title":"Roketler ve Momentum Korunumu","list":{"type":"unordered","items":["Roketlerin çalışmasında momentum korunumu prensibi kullanılır; roketin kendini yukarı doğru fırlatması için yakıtını aşağı doğru fırlatması gerekir.","Başlangıçta roketin hızı sıfır olduğunda, yukarı doğru momentumun büyüklüğünün aşağı doğru momentumun büyüklüğüne eşit olması gerekir.","Roket gazının aşağı doğru momentumu (Δm × v_gaz) roketin yukarı doğru fırlama momentumuna eşit olmalıdır."]},"beginTime":1946,"endTime":2028,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1946&ask_summarization=1"},{"index":16,"title":"Momentum Korunumu Örneği","list":{"type":"unordered","items":["Hava sürtünmesi ihmal edilen ortamda yerden 80 metre yükseklikten serbest bırakılan cisim, 2 saniye sonra iç patlama geçirerek iki eşit parçaya ayrılıyor.","Cisim 2 saniye sonra 20 m/s hızla düşer ve patlama öncesi momentumu 40 kg·m/s aşağı yönlüdür.","Parçalardan biri sola doğru 30 m/s hızla fırladığında, diğer parçanın sağa doğru 30 m/s ve aşağı doğru 40 m/s hızla fırlaması gerekir.","Diğer parçanın hızı, 30² + 40² = 50 m/s olur."]},"beginTime":2028,"endTime":2280,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=2028&ask_summarization=1"},{"index":17,"title":"Roket Momentumu Hesaplama","list":{"type":"unordered","items":["80 kilogramlık yakıt 1600 lük hızla püskürtülüyor ve roketin momentumu korunması için yakıtın momentumu ile roketin momentumu birbirini yok ediyor.","Roketin başlangıç momentumu sıfır iken, yakıt atıldıktan sonra roketin momentumu değişim gösteriyor ve bu değişim 1600×80=128000 değerine eşit oluyor.","Yakıt atıldıktan sonra roketin kütlesi 800 kg'ye düşüyor ve momentum korunması için roketin hızındaki değişim 160 m/s olmalıdır."]},"beginTime":2296,"endTime":2376,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=2296&ask_summarization=1"},{"index":18,"title":"İç Patlama Problemi","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemin O noktasında duran bir cisim iç patlama sonucu 1, 2, 3 kütleye sahip üç parçaya ayrılıyor ve patlama sonrası kütle merkezi korunması gerekiyor.","Kütle merkezi yöntemiyle, parçaların kütlesi birbirine eşit çıkıyor çünkü O noktasında buluşması için m1 ve m2'nin eşit olması ve m3'ün de 1 olması gerekiyor.","Momentum korunumu yöntemiyle de, patlama öncesi momentum sıfır olduğu için patlama sonrası momentumların toplamı da sıfır olmalı ve bu da parçaların kütlesinin birbirine eşit olduğunu gösteriyor."]},"beginTime":2376,"endTime":2546,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=2376&ask_summarization=1"},{"index":19,"title":"İkinci İç Patlama Problemi","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemde 5 kg'lık cisim 4 m/s hızla giderken iç patlama geçirerek üç parçaya ayrılıyor ve parçaların ikisi belirli bir şekilde hareket ediyor.","Patlama öncesi cismin momentumu 20 m/s'e eşit ve patlama sonrası momentum korunması için bu değer korunmalıdır.","Parçaların bileşenleri hesaplanarak, üçüncü parçanın hızının 6 m/s olduğu bulunuyor."]},"beginTime":2546,"endTime":2715,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=2546&ask_summarization=1"},{"index":20,"title":"Top Arabası Problemi","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemde duran bir top arabasından 20 kg'lık mermi 500 m/s hızla fırlatılıyor ve mermi 37 derece açıyla hareket ediyor.","Mermiye ait momentum 10000 değerine sahip olup, bu momentumun 8000 değerinin sağa doğru, 6000 değerinin yukarı doğru bileşenleri bulunuyor.","Momentum korunması için top arabasının sola doğru 8000 değerinde momentum olması gerekiyor ve 1600 kg'lık top arabasının hızı 5 m/s olarak hesaplanıyor."]},"beginTime":2715,"endTime":2897,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=2715&ask_summarization=1"},{"index":21,"title":"Toplu Araba Sorusu Çözümü","list":{"type":"unordered","items":["Toplu araba sorusu, bir kilogramlık cismin 10 metre/saniye hızla gelip arabaya yapışması durumunda, araba ve topun birlikte hangi hızla hareket edeceklerini sorgulayan bir problem.","Sorunun çözüm mantığı momentumun korunumu prensibine dayanır; ilk momentum (çarpışma öncesi) ve son momentum (çarpışma sonrası) eşitlenir.","Topun momentumu 10 metre/saniye hızıyla 37 derece açıyla hareket ettiğinden, yatay bileşeni 8, dikey bileşeni 6 olarak hesaplanır."]},"beginTime":2902,"endTime":3027,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=2902&ask_summarization=1"},{"index":22,"title":"Momentum Hesaplamaları","list":{"type":"unordered","items":["Arabanın aşağı doğru hareket etme şansı yoktur çünkü yerden tepki alır, bu nedenle sadece sağa doğru 20 metre/saniye momentumla hareket eder.","Top ve aracın birlikte kütlesi 4 kilogram olduğundan, toplam momentum 20 olduğunda hız 5 metre/saniye olarak hesaplanır."]},"beginTime":3027,"endTime":3095,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=3027&ask_summarization=1"},{"index":23,"title":"Kayık Sorusu 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testleri çözdükten sonra soru çözüm videolarını izleyebilirler."]},"beginTime":3295,"endTime":3352,"href":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=3295&ask_summarization=1"}],"linkTemplate":"/video/preview/5564284896829901177?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"Thrust and Momentum -3 | 2024 AYT Physics camp","related_orig_text":"Universe Momentum","related_porno":false,"related_less_3m_off":true,"client":"d2d","no_cnt":1,"related_src":"serp","related":"{\"porno\":false,\"vfp\":1,\"orig_text\":\"Universe 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başlayıp, çarpışmaların esnek ve esnek olmayan olarak iki kategoride incelenmesine geçiyor. İlk bölümde merkezi esnek çarpışmalar, ikinci bölümde merkezi olmayan esnek ve esnek olmayan çarpışmalar ele alınırken, son bölümde sürtünmesiz yatay düzlemde hareket eden cisimlerin çarpışması ve kenetlenmesi ile ilgili çeşitli problemler çözülmektedir.","Videoda momentum korunumu denklemleri (p₁ + p₂ = p₁' + p₂ ve m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂) detaylı olarak açıklanmakta, vektörel yöntemler gösterilmekte ve farklı doğrultularda hareket eden cisimlerin çarpışmaları örneklerle anlatılmaktadır. Video, patlamalar ve karmaşık soruların ele alınacağı bilgisiyle sonlanmaktadır."]},"endTime":1905,"title":"11. Sınıf Fizik Dersi: Momentum Korunumu ve Çarpışmalar","beginTime":0}],"fullResult":[{"index":0,"title":"Momentum Korunumu","list":{"type":"unordered","items":["Bu hafta momentum çekimlerinin devamı olarak momentum korunumu, çarpışma olayları ve esnek-esnek olmayan çarpışmalar incelenecek.","Momentum, enerji gibi korunumlu bir büyüklük olup, herhangi bir dış etki veya sürtünme yoksa korunur.","Tüm çarpışma ve patlama olaylarında momentum korunur."]},"beginTime":0,"endTime":53,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=0&ask_summarization=1"},{"index":1,"title":"Esnek ve Esnek Olmayan Çarpışmalar","list":{"type":"unordered","items":["Çarpışmalar esnek ve esnek olmayan olmak üzere iki kategoride incelenir.","Esnek çarpışmalarda hem momentum hem de kinetik enerji korunur.","Esnek olmayan çarpışmalar da incelenecektir."]},"beginTime":53,"endTime":101,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=53&ask_summarization=1"},{"index":2,"title":"Merkezi Esnek Çarpışma","list":{"type":"unordered","items":["Merkezi esnek çarpışmada cisimler çarpıştıktan sonra gelme doğrultularında hareket eder, doğrultu değişikliği olmaz.","Merkezi esnek çarpışmada momentum korunur: p₁ + p₂ = p₁' + p₂' (vektörel toplam şeklinde).","Esnek çarpışmada kinetik enerji de korunur: m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'."]},"beginTime":101,"endTime":234,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=101&ask_summarization=1"},{"index":3,"title":"Merkezi Esnek Çarpışma Örneği","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemde verilen hızlarla hareket eden cisimler merkezi esnek çarpışma yapıyor.","Çarpışma öncesi momentum: 6v₁ + 8v₂ = 6v₁' + 2v₂'.","Çarpışma sonrası hızlar: v₁' = 6 m/s ve v₂' = 10 m/s olarak bulunur."]},"beginTime":234,"endTime":381,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=234&ask_summarization=1"},{"index":4,"title":"Merkezi Esnek Çarpışmanın Özel Durumları","list":{"type":"unordered","items":["Esnek çarpışma yapan cisimlerin momentumları eşit büyüklükte ise (m₁v₁ = m₂v₂), cisimler geldikleri hızlarla geri dönerler.","Kütleleri eşit olan cisimler çarpıştığında hızlarını birbirlerine aktarırlar.","Bu özel durumlar, uzun hesaplamaları yapmadan çözüm yapmayı kolaylaştırır."]},"beginTime":381,"endTime":549,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=381&ask_summarization=1"},{"index":5,"title":"Merkezi Olmayan Esnek Çarpışmalar","list":{"type":"unordered","items":["Merkezi olmayan esnek çarpışmada cisimler farklı doğrultularda hareket eder ve bu durumda momentum korunumu vektörel olarak yapılabilir.","Momentum vektörel olarak korunur, bu nedenle başlangıçtaki momentum (m₁v₁) çarpışma sonrası momentumların toplamına eşittir.","Çarpışma sonrası saçılma açıları toplamı 90 derece olur çünkü esnek çarpışmada kinetik enerji korunur ve Pisagor teoremi uygulanır."]},"beginTime":557,"endTime":880,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=557&ask_summarization=1"},{"index":6,"title":"Esnek Çarpışma Örnekleri","list":{"type":"unordered","items":["Eşit kütleli cisimler merkezi olmayan esnek çarpışmada, çarpışma sonrası momentumların toplamı başlangıç momentumuna eşittir.","Vektörel işlem yaparak çarpışma sonrası hızlar bulunabilir, bu yöntem matematiksel işlemlerden daha pratiktir.","Eğik düzlemde verilen problemlerde, momentum vektörleri kullanılarak çarpışma sonrası hızlar hesaplanabilir."]},"beginTime":880,"endTime":1107,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=880&ask_summarization=1"},{"index":7,"title":"Esnek Olmayan Çarpışmalar","list":{"type":"unordered","items":["Esnek olmayan çarpışmalarda momentum korunur ancak kinetik enerji korunmaz.","Esnek olmayan çarpışmalarda kütleler birlikte hareket ederken, esnek çarpışmalarda kütleler ayrı ayrı hareket eder.","Esnek olmayan çarpışmada, çarpışmadan önceki momentum (m₁v₁ + m₂v₂) çarpışmadan sonraki ortak momentum (n₁ + m₂)v₀'e eşittir."]},"beginTime":1107,"endTime":1238,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1107&ask_summarization=1"},{"index":8,"title":"Kinetik Enerji ve Momentum Problemleri","list":{"type":"unordered","items":["Bir cismin kinetik enerjisi hesaplanarak, başlangıçtaki 10 kg·m²/s² kinetik enerjisinin son durumda 8 kg·m²/s²'ye düşmesi ve %20'sinin kaybolduğu belirtiliyor.","Sürtünmesiz yatay düzlemde hareket eden cisimlerin çarpışıp kenetlenmesi durumunda, momentum korunumu kullanılarak son hızın 12,5 m/s olduğu hesaplanıyor.","Sürtünmesiz yatay düzlemde serbest bırakılan 3m kütleli cismin, önce Y sonra Z cisimleriyle çarpışıp kenetlenmesi durumunda, ortak kütlenin çıkabileceği maksimum yüksekliğin 45,4 metre olduğu bulunuyor."]},"beginTime":1244,"endTime":1534,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1244&ask_summarization=1"},{"index":9,"title":"Momentum ve Enerji Korunumu Problemleri","list":{"type":"unordered","items":["Sürtünmesiz yatay düzlemde hareket eden m₁ ve m₂ kütleli cisimlerin çarpışıp kenetlenmesi durumunda, m₁/m₂ oranı 2 olarak hesaplanıyor.","Kütlesi 4 kg ve 8 kg olan cisimlerin yay sıkıştırılarak birbirine bağlanması ve ip kesildiğinde, kinetik enerjilerindeki oranın 2 olduğu bulunuyor.","Yatay düzlemde 20 m/s hızla hareket eden 4 kg kütleli aracı, atılan 1 kg kütleli cisim çarpıp yapıştığında, toplam kütlenin hızının 20 m/s olduğu hesaplanıyor."]},"beginTime":1534,"endTime":1758,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1534&ask_summarization=1"},{"index":10,"title":"Saplanma ve Momentum Problemi","list":{"type":"unordered","items":["Kütlesi 0,5 kg olan bir cismin 9,5 kg kütleli bir cisme çarpıp saplanması durumunda, cisimlerin birlikte en çok 125 cm yüksekliğine çıkabildiği belirtiliyor.","Saplanma hızının 5 m/s olduğu ve momentum korunumu kullanılarak, cismin başlangıç hızının 100 m/s olduğu hesaplanıyor.","Video, patlamalar ve karmaşık soruların ele alınacağı belirtilerek sonlandırılıyor."]},"beginTime":1758,"endTime":1888,"href":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=1758&ask_summarization=1"}],"linkTemplate":"/video/preview/1981236190135364140?parent-reqid=1765287299868247-12886664136453715704-balancer-l7leveler-kubr-yp-sas-56-BAL&text=Universe+Momentum&t=%%timestamp%%&ask_summarization=1"},"isAdultDoc":false,"relatedParams":{"text":"11.Sınıf Fizik - İtme ve Momentum -2 | 2022","related_orig_text":"Universe Momentum","related_porno":false,"related_less_3m_off":true,"client":"d2d","no_cnt":1,"related_src":"serp","related":"{\"porno\":false,\"vfp\":1,\"orig_text\":\"Universe 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