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İçerikte tek boyutlu ve iki boyutlu momentum problemleri, esnek ve esnek olmayan çarpışmalar, roketlerin çalışma prensibi, iç patlamalar ve kütle merkezi hızı gibi konular örneklerle açıklanmaktadır. Ayrıca kinetik enerji ve momentum arasındaki ilişki de incelenmektedir.","Videoda ÖSYM tarzı sorular çözülerek konular pekiştirilmekte, momentum-grafik ilişkisi gösterilmekte ve farklı çözüm yöntemleri adım adım anlatılmaktadır. Astronotların uzayda hareketi, roketlerin çalışma prensibi, yay sıkıştırma durumları ve top-araba çarpışması gibi pratik uygulamalarla konunun anlaşılması kolaylaştırılmaktadır."]},"endTime":4933,"title":"Fizik Dersi: İtme, Çizgisel Momentum ve Çarpışma Problemleri","beginTime":0}],"fullResult":[{"index":0,"title":"İtme ve Çizgisel Momentum Konusunun İçeriği","list":{"type":"unordered","items":["Video itme, çizgisel momentum, çarpışmalar, iç patlamalar ve roket soruları konularını içerecektir.","ÖSYM tarzı bir soru çözülecek ve bilgiler pekiştirilecektir."]},"beginTime":7,"endTime":49,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=7&ask_summarization=1"},{"index":1,"title":"İtme Kavramı","list":{"type":"unordered","items":["İtme, kuvvetle zamanın çarpımıdır ve İ harfi ile gösterilir (İ = F × Δt).","İtme vektörel bir büyüklüktür, yani yönü önemlidir ve birimi newton-saniyedir.","İtme hesaplanırken kuvvetlerin yönleri sayı doğrusuna göre artı ve eksi olarak belirlenir."]},"beginTime":49,"endTime":192,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=49&ask_summarization=1"},{"index":2,"title":"İtme Hesaplama Örnekleri","list":{"type":"unordered","items":["İtme hesaplaması için net kuvvetle etki süresinin çarpımı yapılır (İ = (F₁ + F₂ + ...) × Δt).","Kuvvet-zaman grafiğinde itme, altta kalan alan olarak hesaplanır.","Aynı yöndeki kuvvetler toplanır, zıt yöndeki kuvvetler çıkarılır."]},"beginTime":192,"endTime":365,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=192&ask_summarization=1"},{"index":3,"title":"Çizgisel Momentum","list":{"type":"unordered","items":["Çizgisel momentum, cismin kütlesi ile çizgisel hızının çarpımından oluşur (p = m × v).","Momentum da vektörel bir büyüklüktür ve birimi kilogram-metre/saniyedir.","Aynı büyüklükte olan iki momentum, yönleri farklı olduğunda etkileri de farklı olur."]},"beginTime":365,"endTime":537,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=365&ask_summarization=1"},{"index":4,"title":"Momentum-Zaman Grafiği","list":{"type":"unordered","items":["Hız-zaman grafiğinden momentum-zaman grafiğine geçerken, şekil aynı kalır.","Momentum değerleri, hız değerlerinin kütle ile çarpımından bulunur.","Kütle skaler bir nicelik olduğu için grafiğin şekline etkisi olmaz, sadece bir katsayı olarak kullanılır."]},"beginTime":537,"endTime":639,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=537&ask_summarization=1"},{"index":5,"title":"Grafikler ve Çizgisel Momentum","list":{"type":"unordered","items":["Mekanikteki konular birbirlerinin içinde olduğundan, bazı soruları pek çok yöntemle çözebiliriz.","Momentum formülü p = m × v'den kütleyi bulmak için momentumu hıza bölmek gerekir.","Grafiğin eğimi (tanjant alfa) kütleyi verir, bu örnekte eğim 10/5 = 2 olduğundan kütlenin 2 kg olduğu görülür."]},"beginTime":643,"endTime":707,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=643&ask_summarization=1"},{"index":6,"title":"İtme ve Çizgisel Momentum Arasındaki İlişki","list":{"type":"unordered","items":["İtme, kuvvet çarpı zaman değişimi (F × Δt) olarak tanımlanır.","Newton'un ikinci yasası (F = m × a) kullanılarak itme formülü m × a × Δt olarak yazılabilir.","İtme, momentum değişimi (Δp) olarak ifade edilir ve bu iki niceliğin birimleri (kg·m/s) birbirine eşittir."]},"beginTime":707,"endTime":878,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=707&ask_summarization=1"},{"index":7,"title":"Momentum Değişimi Hesaplama","list":{"type":"unordered","items":["Momentum değişimi, son momentumdan ilk momentumu çıkartarak bulunur: Δp = p₂ - p₁.","Vektörel hesaplamalarda yönlerin (+ veya -) doğru şekilde yazılması önemlidir.","İtme ve momentum değişimi aynı büyüklüğü ifade eder, bir itme varsa cisimde momentum değişimi olur."]},"beginTime":878,"endTime":1015,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=878&ask_summarization=1"},{"index":8,"title":"Grafik Sorularında İtme ve Momentum","list":{"type":"unordered","items":["İtme-momentum ilişkisi bilgisiyle, F-t grafiğindeki alan hesaplaması itme değerini verir.","İtme ve momentum değişimi biliniyorsa, ilk momentum biliniyorsa son momentum bulunabilir.","İtme-momentum ilişkisi tek boyutta değil, iki boyutta da (x-y ekseninde) geçerlidir ve vektörel olarak hesaplanır."]},"beginTime":1015,"endTime":1268,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1015&ask_summarization=1"},{"index":9,"title":"Momentum Değişimi Hesaplama","list":{"type":"unordered","items":["Cismin son momentumu yukarı doğru 6 birim, ilk momentumu ise 24 birim olup, vektör çıkarma işlemi yapılacaktır.","Vektör çıkarmalarda eksi işaret sadece yönünü değiştirir, bu nedenle iki vektör birbirleriyle dik olduğunda hipotenüs 6√2 birim olacaktır.","Δp (momentum değişimi) 6√2 Newton-saniye büyüklüğünde, X ekseniyle 45 derece açı yapacak şekilde olacaktır."]},"beginTime":1272,"endTime":1418,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1272&ask_summarization=1"},{"index":10,"title":"Momentum Korunumu","list":{"type":"unordered","items":["Momentum korunumu, bir dış kuvvet uygulanmadığında (itme olmadığı durumda) momentum değişiminin sıfır olması durumudur.","Momentum korunumu çarpışmalarda ve iç patlamalarda önemlidir.","Çarpışmalarda iki tip vardır: esnek çarpışma ve esnek olmayan çarpışma."]},"beginTime":1418,"endTime":1479,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1418&ask_summarization=1"},{"index":11,"title":"Esnek Olmayan Çarpışma","list":{"type":"unordered","items":["Esnek olmayan çarpışmalarda \"kenetlenme\", \"yapışma\" ve \"birlikte hareket\" kelimeleri kullanılır.","Kenetlenme durumunda cisimler çarpıştıktan sonra birlikte hareket eder ve ortak kütlenin hızı bulunur.","Kenetlenme sırasında kütle kaybı yoktur, yani cisimler birleştiğinde toplam kütle değişmez."]},"beginTime":1479,"endTime":1591,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1479&ask_summarization=1"},{"index":12,"title":"Kenetlenme Problemi Çözümü","list":{"type":"unordered","items":["Kenetlenme durumunda momentum korunumu kullanılarak ilk ve son momentumlar eşitlenir.","İlk momentum hesaplanır ve son momentumda ortak kütle ve hız bilinmeyen olarak kullanılır.","Hızın yönü ve büyüklüğü momentum değişimi denkleminden bulunur."]},"beginTime":1591,"endTime":1705,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1591&ask_summarization=1"},{"index":13,"title":"İki Boyutlu Kenetlenme Problemi","list":{"type":"unordered","items":["İki boyutlu kenetlenme probleminde cisimlerin sabit hızları ve çarpışma noktasına ulaşma süreleri hesaplanır.","İlk momentum vektörleri hesaplanır ve momentum korunumu kullanılarak son momentumun yönü bulunur.","Ortak hız, toplam kütle ve momentum ilişkisi kullanılarak hesaplanabilir."]},"beginTime":1705,"endTime":1919,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1705&ask_summarization=1"},{"index":14,"title":"Momentum Soruları ve Çözüm Yöntemleri","list":{"type":"unordered","items":["Momentum sorularında, itme kuvveti olmadığı durumlarda ilk ve son momentumların birbirine eşit olduğu belirtilir.","Momentum problemlerinde matematiksel hesaplamalar yerine şekil üzerinden göstermek daha faydalıdır, bu da yeni fikirlerin gelmesine ve soruyu farklı şekilde çözmeye sebep olabilir.","Momentum sorularında, cisimler birleştiğinde ortak hızı bulmak için momentum ve toplam kütle kullanılır."]},"beginTime":1922,"endTime":2112,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1922&ask_summarization=1"},{"index":15,"title":"Mermi ve Takoza Çarpma Problemi","list":{"type":"unordered","items":["Mekanikte momentum, itme ve enerji gibi farklı konular altında sorular çıkabilir, ancak temel bilgiye sahip olmak önemlidir.","Mermi-takoza çarpma probleminde iki adım vardır: önce momentum korunumu ile ortak hızı bulmak, sonra enerji korunumu ile yükselti hesaplamak.","Durgun cisimlerin çizgisel momentumu yoktur, bu önemli bir bilgidir."]},"beginTime":2112,"endTime":2293,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2112&ask_summarization=1"},{"index":16,"title":"Enerji Korunumu ve Yükselti Hesaplama","list":{"type":"unordered","items":["Cisimler birleştiğinde kinetik enerjileri potansiyel enerjiye dönüşür, bu durumda kinetik enerji sıfır olur.","Yerçekimi ivmesi (g) genellikle 10 m/s² olarak alınır, ancak kutuplarda 10 değeridir, ekvatorda ise biraz daha azalır.","Mermi-takoza çarpma probleminde, ilk durumda kinetik enerji ile son durumda potansiyel enerji eşitlenerek yükselti hesaplanır."]},"beginTime":2293,"endTime":2463,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2293&ask_summarization=1"},{"index":17,"title":"Merkezi Esnek Çarpışmalar","list":{"type":"unordered","items":["Merkezi esnek çarpışmalarda momentum korunur, aynı zamanda enerji de korunur.","Esnek çarpışmalarda hızda da korunma vardır, yani çarpışmadan önceki hızların vektörel toplamı, çarpışmadan sonraki hızların vektörel toplamına eşittir.","Merkezi esnek çarpışmalar problemlerinde, iki cismin her ikisinin de hızını bulmak için momentum korunumu ve enerji korunumu denklemlerinden iki denklem kurularak çözüme gidilir."]},"beginTime":2463,"endTime":2579,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2463&ask_summarization=1"},{"index":18,"title":"Momentum Korunumu ve Çarpışma Problemleri","list":{"type":"unordered","items":["İlk ve son momentumlar birbirine eşit olacak şekilde momentum korunumu kanunu kullanılır.","İlk momentum sistemin ilk momentumunu, son momentum ise çarpışmadan sonra cisimlerin momentumlarını gösterir.","Momentum korunumu ve kütlenin korunumu ilişkileri kullanılarak çarpışma problemleri çözülebilir."]},"beginTime":2581,"endTime":2755,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2581&ask_summarization=1"},{"index":19,"title":"Kütle Merkezi Yöntemi","list":{"type":"unordered","items":["Çarpışma problemlerini çözerken ilk önce kütle merkezinin hızını bulmak gerekir.","Kütle merkezi hızı, toplam momentumun toplam kütleye bölümüdür.","Bir cismin son hızını bulmak için kütle merkezi hızının iki katından o cismin ilk hızını çıkartmak gerekir."]},"beginTime":2755,"endTime":2861,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2755&ask_summarization=1"},{"index":20,"title":"Esnek Çarpışma Kuralları","list":{"type":"unordered","items":["Merkezi esnek çarpışmalarda, cisimlerin kütleleri eşit ise hızlarını değiş tokuş ederler.","Cisimlerin ilk momentumları eşit büyüklükte ise, çarpışmadan sonra aynı hızla zıt yönlere giderler.","Eşit kütleli cisimler esnek çarpışma yaparken hızlarını değiştirirler, kütleleri eşit değilse ise hızları değişir."]},"beginTime":2861,"endTime":2959,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2861&ask_summarization=1"},{"index":21,"title":"Örnek Soru Çözümü","list":{"type":"unordered","items":["Eşit kütleli cisimler sürtünmesiz sistemde farklı yüksekliklerden serbest bırakılır ve çarpışır.","Cisimlerin ilk hızları, düşüş yüksekliklerine göre hesaplanabilir (1 birim yükseklik = v, 4 birim yükseklik = 2v).","Çarpışmadan sonra cisimler hızlarını değiştirerek farklı noktalara ulaşır."]},"beginTime":2959,"endTime":3170,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2959&ask_summarization=1"},{"index":22,"title":"Sinüs ve Kosinüs Değerleri","list":{"type":"unordered","items":["Sorularda genellikle sinüs 37 ve sinüs 53 değerleri verilir, bunların değerleri sırasıyla 6 ve 8'dir.","Birbirlerini 90'a tamamlayan açılarda, birinin sinüsü diğerinin kosinüs değerine eşittir."]},"beginTime":3172,"endTime":3199,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3172&ask_summarization=1"},{"index":23,"title":"Esnek Çarpışma Problemi Çözümü","list":{"type":"unordered","items":["Soruda esnek çarpışma yapılmış iki cismin hızları ve k/L oranının bulunması isteniyor.","İlk durumda y ekseninde momentum yokken, son durumda y eksenindeki momentumların toplamı sıfır olmalıdır.","X eksenindeki momentumlar eşitlenerek cisimlerin hızları hesaplanabilir."]},"beginTime":3199,"endTime":3515,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3199&ask_summarization=1"},{"index":24,"title":"İç Patlamalar","list":{"type":"unordered","items":["İç patlamalarda cisim bir bütün halinden sonra parçalara ayrılır, ancak dışarıdan kuvvet olmadığı için ilk ve son momentumlar eşittir.","İlk momentum sıfır ise, son momentumların toplamı da sıfır olmalıdır.","Momentumlar x ve y koordinatlarına göre ayrılır ve karelerinin karekökü alınarak toplam momentum bulunur."]},"beginTime":3515,"endTime":3739,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3515&ask_summarization=1"},{"index":25,"title":"Momentum Eşitliği Uygulaması","list":{"type":"unordered","items":["İlk durumda momentum sıfır olmayabilir, cismin hızı zamanla değişebilir.","Eşit kütleli parçalara ayrılan cismin momentumu, parçaların momentumlarının toplamına eşittir.","Momentum eşitliğinden, bilinen değerler kullanılarak bilinmeyen hızlar bulunabilir."]},"beginTime":3739,"endTime":3923,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3739&ask_summarization=1"},{"index":26,"title":"Uzay Boşluğunda Momentum Korunumu","list":{"type":"unordered","items":["Uzay boşluğunda hareket eden bir astronot, elindeki bir cisim (örneğin kalem) ileri doğru attığında kendisi geri doğru gider.","İlk durumda momentum sıfır olan sistemin, cisim atıldığında momentum korunması gereği, cismin ileri gidişine karşılık astronot geri gider.","Cismin kütlesi astronottan daha az olduğu için, astronot daha yavaş ilerler, ancak momentum değerleri eşittir."]},"beginTime":3926,"endTime":4057,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3926&ask_summarization=1"},{"index":27,"title":"Roketler ve Momentum","list":{"type":"unordered","items":["Roketlerde durum aynıdır; gaz yakılıp arkaya doğru püskürtüldüğünde, roket ileri doğru ilerler.","Roket ve gazların momentumları toplamı sıfır olmalıdır: Mb_roket × V_roket = M_gaz × V_gaz.","Gazı geriye doğru ittiğimizde, kendimiz ileriye doğru gideriz."]},"beginTime":4057,"endTime":4109,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=4057&ask_summarization=1"},{"index":28,"title":"Yay Sıkıştırma Sorusu","list":{"type":"unordered","items":["Yay 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çözülebilir."]},"beginTime":4183,"endTime":4242,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=4183&ask_summarization=1"},{"index":30,"title":"Top ve Araç Çarpışması","list":{"type":"unordered","items":["Top araca çarpıp yapıştığında, ilk momentum ve son momentum eşit olmalıdır.","Yatay zemindeki araç yerin içine giremeyeceğinden, sadece yatay momentumlar dikkate alınmalıdır.","Top ve araç yapıştığında toplam kütlenin çarpı ortak hızı, çarpışmadan önceki momentuma eşittir."]},"beginTime":4242,"endTime":4375,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=4242&ask_summarization=1"},{"index":31,"title":"Kinetik Enerji ve Momentum 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+ m₂)) kullanılarak, ilk hızın 8/3 m/s olduğu bulunuyor."]},"beginTime":4547,"endTime":4693,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=4547&ask_summarization=1"},{"index":33,"title":"Potansiyel Enerji ve Yükseklik İlişkisi","list":{"type":"unordered","items":["Bir cismin farklı yüksekliklerden fırlatılması durumunda, kinetik enerjileri hızın karesiyle orantılıdır.","Potansiyel enerji (mgh) formülünde yerçekimi (g) aynı sistemde olduğu için atılabilir, potansiyel enerji ile yükseklik birbirleriyle orantılıdır.","Yüksekliklerin oranını bulmak için potansiyel enerjilerin oranını almak yeterlidir."]},"beginTime":4693,"endTime":4827,"href":"/video/preview/1036552894710627436?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=4693&ask_summarization=1"},{"index":34,"title":"Yay ve Enerji İlişkisi","list":{"type":"unordered","items":["Cisim yayın üzerine düşerken, yayın sıkışma miktarı (x) ve cismin yüksekliği (h) arasındaki ilişkiyi bulmak için 1/2 kx² = mgh + mgx formülü kullanılır.","Cisim hareket halindeyken, enerji denklemine cismin kinetik enerjisi (1/2 mv²) de eklenmelidir.","İlk durumdaki enerji ile son durumdaki enerji arasındaki denklem kurularak sorunun çözümü 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Dersimiz #Fizik in önemli konularından "İtme ve Çizgisel Momentum". Hazırsan öğrenme garantili ca...","preview":{"posterSrc":"//avatars.mds.yandex.net/get-vthumb/1770987/a25aaecac1fc102fffa7b6b9026f8017/564x318_1","videoSrc":"https://video-preview.s3.yandex.net/yBUlHQIAAAA.mp4","videoType":"video/mp4"},"target":"_self","position":"19","reqid":"1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL","summary":{"isFull":true,"fullTextUrl":"/video/result?ask_summarization=1&numdoc=1&noreask=1&nomisspell=1&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=videoid:16097362655869464962","teaser":[{"list":{"type":"unordered","items":["Bu video, Tonguç Akademi'de bir öğretmenin canlı yayın formatında fizik dersi anlattığı eğitim içeriğidir. Öğretmen, öğrencilere sorular sorarak interaktif bir şekilde dersi işlemektedir.","Video, momentum ve itme kavramlarını detaylı şekilde ele almaktadır. İlk olarak momentum kavramı (p = m × v) ve vektörel bir büyüklük olduğu açıklanmakta, ardından itme kavramı (ı = F × Δt ve ı = Δp) anlatılmaktadır. Daha sonra momentum korunumu prensibi, esnek ve esnek olmayan çarpışmalar, patlama olayları ve açılı çarpışmalar konuları örneklerle açıklanmaktadır.","Videoda ayrıca kuvvet-zaman grafiği alanlarının nasıl hesaplanacağı, momentum değişimi hesaplamaları, vektörel çıkarma işlemleri ve günlük hayattan örnekler üzerinden konu pekiştirilmektedir. Üniversite sınavlarına hazırlanan öğrenciler için önemli bilgiler içeren ders, sonunda tüm formüller özetlenmekte ve öğrencilere yazılı sınavı hazırlamak için videoların tekrar izlenmesi tavsiye edilmektedir."]},"endTime":3955,"title":"Fizik Dersi: Momentum ve İtme Konusu","beginTime":0}],"fullResult":[{"index":0,"title":"Dersin Tanıtımı","list":{"type":"unordered","items":["Tonguç Akademi'de itme ve momentum konusunda canlı yayın yapılacak.","Öğrenciler canlı sohbetten sorular soracak ve eğitmen paralel olarak soruları çözecek.","Dersin sonunda Kan Plus kitabından ödev verilecek."]},"beginTime":5,"endTime":53,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=5&ask_summarization=1"},{"index":1,"title":"Ders Programı","list":{"type":"unordered","items":["Aralıktaki programda enerji konusu yapılmış ve bugün itme momentum konusu ele alınacak.","Kitapta sayfa 48'den başlayıp 56'ya kadar çarpışmalar ve ÖSYM testleri konuları işlenecek.","Öğrenciler kamp videoları, video çözümleri ve öğrenci ek sorularına karekodlarla ulaşabilecekler."]},"beginTime":53,"endTime":144,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=53&ask_summarization=1"},{"index":2,"title":"Momentum Kavramı","list":{"type":"unordered","items":["Çizgisel momentum, cisimlerin çarpışması anlamına gelir ve düz yolda giden cisimlerin momentumu incelenir.","Çarpışma olayında sadece kütle veya hız yeterli değil, yeni bir kavram tanımlanması gerekir.","Momentum, kütle ve hızın çarpımıdır ve P harfi ile gösterilir (P = m × v)."]},"beginTime":144,"endTime":371,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=144&ask_summarization=1"},{"index":3,"title":"Momentum Özellikleri","list":{"type":"unordered","items":["Momentum vektörel bir büyüklüktür ve üzerine ok işareti konulur.","Momentumun yönü, hız vektörüyle aynı yönlüdür.","Momentumun birimi kilogram metre bölü saniyedir (kg·m/s)."]},"beginTime":371,"endTime":447,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=371&ask_summarization=1"},{"index":4,"title":"Momentum Kavramı","list":{"type":"unordered","items":["Momentum, cismin kütlesi ve hızının çarpımıdır ve vektörel bir büyüklüktür, yönü önemlidir.","Momentum hesaplanırken cismin yönüne dikkat edilmelidir; sola giden cisimlerin momentumu eksi, sağa giden cisimlerin momentumu artı olarak yazılır.","Momentum, sadece kütleye değil, hızına da bağlıdır; aynı hızda giden farklı kütleli cisimler farklı momentumlara sahiptir."]},"beginTime":451,"endTime":610,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=451&ask_summarization=1"},{"index":5,"title":"Momentum Örnekleri","list":{"type":"unordered","items":["Her hareket eden cisim momentuma sahiptir; yürüyen bir insan, scooter ile giden biri, araba gibi.","Bir kişinin yaklaşık momentumu, kütlesi ve hızı ile hesaplanabilir (örneğin 70 kg bir kişi 2 m/s hızla yürüyorsa momentumu 140 kg·m/s olur).","Bir arabanın momentumu, kütlesi ve hızı ile hesaplanabilir (örneğin 1000 kg bir araba 80 m/s hızla giderse momentumu 80.000 kg·m/s olur)."]},"beginTime":610,"endTime":710,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=610&ask_summarization=1"},{"index":6,"title":"İtme Kavramı","list":{"type":"unordered","items":["İtme, bir cisme uygulanan kuvvet ile kuvvetin uygulanma süresinin çarpımından elde edilen vektörel büyüklüktür.","İtmenin formülü İ = F·Δt şeklindedir ve birimi Newton·saniyedir.","İtme, ayrıca İ = Δp formülü ile de hesaplanabilir, yani momentumun değişimi ile ifade edilebilir."]},"beginTime":710,"endTime":916,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=710&ask_summarization=1"},{"index":7,"title":"İtme Soruları","list":{"type":"unordered","items":["İtme sorularında verilen verilere göre İ = F·Δt veya İ = Δp formüllerinden biri kullanılır.","İtme sorularında kuvvet ve süreyi bilinirse İ = F·Δt formülü kullanılır.","İtme sorularında momentum değişimi bilinirse İ = Δp formülü kullanılır."]},"beginTime":916,"endTime":992,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=916&ask_summarization=1"},{"index":8,"title":"İtme Hesaplamaları","list":{"type":"unordered","items":["İtme hesaplamalarında iki farklı formül kullanılabilir: F×t veya momentum değişimi (Δp).","Hangi formülü kullanacağınız, verilen verilere bağlıdır; F ve t verilmişse F×t formülü, momentum değişimi verilmişse Δp formülü kullanılır.","İtme hesaplamalarında her iki formül de aynı sonucu verir."]},"beginTime":996,"endTime":1061,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=996&ask_summarization=1"},{"index":9,"title":"Momentum Değişimi Hesaplama","list":{"type":"unordered","items":["Momentum değişimi (Δp) formülü, ikinci durumdaki momentumdan ilk durumdaki momentum çıkarılarak hesaplanır: Δp = p₂ - p₁.","Momentum, kütle ile hızın çarpımıdır (p = m×v).","İtme ve momentum değişimi aslında aynı şeydir; sana itmeyi sormuşsa da momentum değişimi sormuşsa da aynı formül kullanılır."]},"beginTime":1061,"endTime":1316,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1061&ask_summarization=1"},{"index":10,"title":"Vektörel Hesaplama","list":{"type":"unordered","items":["Momentum değişimi hesaplanırken vektörel çıkarma işlemi yapılır; yönleri dikkate alınmalıdır.","İkinci durumdaki momentumdan ilk durumdaki momentum çıkarılırken, ilk momentumun yönü ters çevrilir.","Top duvara çarparak geri dönerken momentum değişimi hesaplanırken yön değişimi dikkate alınmalıdır."]},"beginTime":1316,"endTime":1452,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1316&ask_summarization=1"},{"index":11,"title":"Momentum Değişimi Hesaplama","list":{"type":"unordered","items":["İlk momentum m×v cinsinden hesaplanır.","Çarpışma sonrası momentum değişimi için ilk momentum yönü ters çevrilerek vektörel çıkarma yapılır.","İki vektör arasında 120 derece açı varsa, bileşkesi vektörlerin toplamına eşittir."]},"beginTime":1454,"endTime":1611,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1454&ask_summarization=1"},{"index":12,"title":"İtme Soruları Çözüm Yöntemi","list":{"type":"unordered","items":["İtme veya momentum değişimi sorularında F×Δt formülü kullanılır.","Atışlarda itme sorulduğunda F×Δt formülü daha uygun olur.","Atışlarda yerçekimi kuvveti m×g (ağırlık) olarak hesaplanır ve süreyi atış formülleriyle buluruz."]},"beginTime":1611,"endTime":1737,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1611&ask_summarization=1"},{"index":13,"title":"İtme Örnek Soruları","list":{"type":"unordered","items":["İtme hesaplamasında F×Δt formülü kullanılır.","Yatay atışta, hız değişimini hesaplayarak süreyi buluruz.","İtme birimleri Newton-saniye cinsinden ifade edilir."]},"beginTime":1737,"endTime":1852,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1737&ask_summarization=1"},{"index":14,"title":"Kuvvet-Zaman Grafiği ve İtme","list":{"type":"unordered","items":["Kuvvet-zaman grafiğinde, eğim yerine alan hesaplanır.","F×t çarpımı için grafiğin altında kalan alanı bulmak gerekir.","Grafiğin altında kalan alan, cisme uygulanan itmenin büyüklüğünü verir."]},"beginTime":1852,"endTime":2012,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=1852&ask_summarization=1"},{"index":15,"title":"İtme ve Momentum Değişimi","list":{"type":"unordered","items":["İtme formülü F×Δt veya Δp (momentum değişimi) olarak ifade edilir ve bu iki formül birbirine eşittir.","İtme problemlerinde, verilen kuvvet ve momentum değişimi bilgileri kullanılarak süreyi bulmak mümkündür.","Momentum değişimi, başlangıç momentumundan son momentuma kadar olan farktır."]},"beginTime":2014,"endTime":2121,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2014&ask_summarization=1"},{"index":16,"title":"İki Cisim Problemi","list":{"type":"unordered","items":["İki cismin aynı çizgisel momentuma ulaşması için F×t₁ = p₁ ve F×t₂ = p₂ formüllerinden yararlanılır.","Aynı hıza ulaşan iki cismin süresi, kütlesi ve hızları arasındaki ilişkiyi kullanarak hesaplanabilir.","Kinetik enerji eşitliği için hızlar arasındaki ilişki, m₁v₁² = m₂v₂² formülüyle bulunabilir."]},"beginTime":2121,"endTime":2356,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2121&ask_summarization=1"},{"index":17,"title":"Momentumun Korunumu","list":{"type":"unordered","items":["Momentumun korunumu, dışarıdan uygulanan net kuvvetin sıfır olduğu durumlarda geçerlidir.","Bir sistemin ilk momentumu ile son momentumu vektörel olarak eşittir.","Buz üzerinde duran iki çocuğun birbirini itmesi durumunda, ilk momentum sıfır ise son momentum da sıfır olmalıdır."]},"beginTime":2356,"endTime":2495,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2356&ask_summarization=1"},{"index":18,"title":"Esnek ve Esnek Olmayan Çarpışmalar","list":{"type":"unordered","items":["Esnek çarpışmada cisimler çarpıştıktan sonra ayrılır, örneğin bilardo topları gibi.","Esnek olmayan çarpışmada cisimler çarpıştıktan sonra yapışır ve beraber gider.","Esnek çarpışmalarda enerji korunurken, esnek olmayan çarpışmalarda enerji korunmaz."]},"beginTime":2495,"endTime":2595,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2495&ask_summarization=1"},{"index":19,"title":"Momentum Kavramı ve Esnek Olmayan Çarpışma","list":{"type":"unordered","items":["Momentum kavramı, cismin kütlesi ile hızının çarpımından oluşur ve çarpışmalarda korunur.","Esnek olmayan çarpışmada, iki cisim birbirine yapışarak ortak bir hız kazanır.","Momentum korunumu, çarpışmadan önceki momentumun çarpışmadan sonraki momentuma eşit olduğu prensiptir."]},"beginTime":2599,"endTime":2658,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2599&ask_summarization=1"},{"index":20,"title":"Esnek Olmayan Çarpışma Örnekleri","list":{"type":"unordered","items":["İlk örnekte, 2 kg kütleli ve 30 m/s hızla giden cisim ile 1 kg kütleli duran cisim çarpıştığında, birleşen cisimlerin ortak hızı 20 m/s olur.","İkinci örnekte, 1 kg kütleli 10 m/s hızla sağa giden ve 4 kg kütleli 20 m/s hızla sola giden cisimler çarpıştığında, birleşen cisimler 14 m/s hızla sola doğru gider.","Çarpışmadan önce tek parça olan kayık ve çocuk sisteminde, çocuk kayıktan 20 m/s hızla atladığında, kayık 8 m/s hızla karşı tarafa gider."]},"beginTime":2658,"endTime":3007,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=2658&ask_summarization=1"},{"index":21,"title":"Esnek Çarpışma","list":{"type":"unordered","items":["Esnek çarpışmada, cisimler birbirine çarptıktan sonra birbirinden ayrılır.","Esnek çarpışmada, ilk cismin çarpışmadan önceki hızı ile çarpışmadan sonraki hızının toplamı, ikinci cismin çarpışmadan önceki hızı ile çarpışmadan sonraki hızının toplamına eşittir.","Çarpışmalar iki şekilde sınıflandırılır: esnek çarpışma (cisimler birbirinden ayrılır) ve esnek olmayan çarpışma (cisimler birbirine yapışır)."]},"beginTime":3007,"endTime":3197,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3007&ask_summarization=1"},{"index":22,"title":"Esnek Çarpışma Problemi Çözümü","list":{"type":"unordered","items":["Esnek çarpışmada cisimler çarptıktan sonra ayrılıyor ve momentum korunumu ile hız korunumu uygulanıyor.","Esnek çarpışmada tek momentum korunumu yeterli olmayabilir, ikinci bir formül de kullanılması gerekebilir.","Çarpışmadan önceki momentum (18+4) ile çarpışmadan sonraki momentum (3vk+2vl) eşitlenerek denklem kurulur."]},"beginTime":3202,"endTime":3318,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3202&ask_summarization=1"},{"index":23,"title":"Esnek Çarpışma Formülü","list":{"type":"unordered","items":["Esnek çarpışmada ikinci formül: v1+vk² = v2+vl² şeklinde kullanılır.","Çarpışmadan önceki hızlar (6 ve -4) ile çarpışmadan sonraki hızlar (vk ve vl) kullanılarak denklem kurulur.","İki denklem çözülerek çarpışmadan sonraki hızlar (vk=-2, vl=8) bulunur."]},"beginTime":3318,"endTime":3414,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3318&ask_summarization=1"},{"index":24,"title":"Patlama Problemi Çözümü","list":{"type":"unordered","items":["Patlama probleminde de momentum korunumu kullanılır.","Bir cisim patlayarak ikiye ayrıldığında, ilk durumda (m+3)×2 momentumu son durumda -5m+27 momentumu eşitlenir.","Denklem çözülerek m=3 kg bulunur ve başlangıçtaki toplam kütleye 6 kg çıkar."]},"beginTime":3414,"endTime":3558,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3414&ask_summarization=1"},{"index":25,"title":"Esnek Çarpışma Kuralları","list":{"type":"unordered","items":["Esnek çarpışmalarda momentumlar eşitse cisimler aynı hızla geri döner.","Kütleler eşitse hızlar yer değiştirir.","Momentumlar eşitse (20+20) cisimler aynı hızla (20+15) geri dönecektir."]},"beginTime":3558,"endTime":3624,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3558&ask_summarization=1"},{"index":26,"title":"Vektörel Momentum Problemi","list":{"type":"unordered","items":["Vektörel momentum probleminde bileşenleri ayırmak yerine vektörel toplama yapılır.","İlk durumda iki cismin momentumları vektörel olarak toplanır.","Açılar kullanılarak v1/v2 oranı 4/3 olarak bulunur."]},"beginTime":3624,"endTime":3708,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3624&ask_summarization=1"},{"index":27,"title":"Fizik Problemi Çözümü","list":{"type":"unordered","items":["Bir cismin oyun hamuruyla çarpışması ve beraber hareket etmesi durumunda, yükselme miktarı hesaplanıyor.","Problemde üçgen oluşturulup, geometrik hesaplamalar yapılıyor; yükseklik 3 metre olarak bulunuyor.","Sorunun çözümü için önce momentum korunumu, sonra enerji korunumu formülleri kullanılıyor."]},"beginTime":3710,"endTime":3786,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3710&ask_summarization=1"},{"index":28,"title":"Momentum ve Enerji Hesaplamaları","list":{"type":"unordered","items":["İlk durumda momentum korunumu uygulanarak, v² = v/2 formülü elde ediliyor.","Enerji korunumu formülü kullanılarak v²/4 = 3g denklemi çözülüyor.","Sonuç olarak cismin hızı 2√6 m/s olarak bulunuyor."]},"beginTime":3786,"endTime":3861,"href":"/video/preview/16097362655869464962?from_type=vast&parent-reqid=1751236046470250-6713940127884365435-balancer-l7leveler-kubr-yp-sas-131-BAL&text=En+kolay+%C3%87izgisel+%C3%A7al%C4%B1%C5%9Fmalar&t=3786&ask_summarization=1"},{"index":29,"title":"Dersin Özeti","list":{"type":"unordered","items":["Çizgisel momentum, itme ve enerji korunumu formülleri anlatılıyor.","Momentum ve itmenin iki 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